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predentalgirl1
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I put all of my questions/solutions in the attached file...could someone please check over them before 7:00 am to see if I have them correct? Thanks in advance!
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chemisttree said:Bonus is wrong. There are 2 chiral centers and neither is near enough to the amine to cause racemization. The amine is not a chiral center.
3- and 4-vinylcyclohexanethiol each have 2 chiral centers.
e) is wrong since Br2 adds anti to double bonds, not randomly. You need to make models to see it maybe.
A chiral center is a carbon atom that is bonded to four different groups. This results in the molecule having two non-superimposable mirror image forms, known as enantiomers.
To determine the number of chiral centers in a molecule, you must look at the carbon atoms and identify those that are bonded to four different groups. These carbon atoms are considered chiral centers.
Markonikov's rule states that in the addition of a hydrogen halide to an unsymmetrical alkene, the hydrogen atom bonds to the carbon atom that already has the most hydrogen atoms bonded to it. This results in the formation of a more stable carbocation intermediate.
Markonikov's rule can affect the formation of chiral centers in certain reactions. For example, the addition of a hydrogen halide to an alkyne can result in the formation of a chiral center if the initial alkene has a chiral center and the addition follows Markonikov's rule.
Yes, a molecule can have multiple chiral centers. The number of chiral centers in a molecule is equal to the number of carbon atoms that are bonded to four different groups. Therefore, a molecule with multiple carbon atoms can have multiple chiral centers.