| New Reply |
Proof rule |
Share Thread | Thread Tools |
| Mar9-13, 10:38 PM | #1 |
|
|
Proof rule
Hello I'm learning about proofs and in my book there's a sect. On mathematical induction. And I'm trying understand why this makes it true for all values.
1+3+5...2n-1=n^2 Suppose that the formula is known to be true for n=1, and suppose that as a result of assuming that it is true for n=k, where k is an arbitrary positive integer, we can prove that it is also true for n=k+1. Then the formula is true for all k. Why does this addition of 1 make it true for all k? |
| Mar9-13, 11:47 PM | #2 |
|
|
You know it's true for n=1 and you know that for every n where it's true, it's also true for n+1. Since you proved it for 1, this implies it's true for 1+1 = 2. Now, since you know it's true for 2, it must be true for 2+1 = 3. Now since you know it's true for 3, it's also true for 3+1 = 4. And so on, so it's true for every positive integer.
|
| New Reply |
| Thread Tools | |
Similar Threads for: Proof rule
|
||||
| Thread | Forum | Replies | ||
| Help in proof of chain rule | Calculus | 2 | ||
| Proof of the chain rule | Calculus & Beyond Homework | 5 | ||
| Rule of 9 proof | Calculus & Beyond Homework | 3 | ||
| Proof of the Quotient Rule | Calculus & Beyond Homework | 5 | ||
| proof of chain rule | Calculus | 2 | ||