HELP Inverse Laplace Transform

Oops I thought he multiplied it out and set it equal to s:rolleyes:In summary, the conversation revolves around solving three different problems involving inverse Laplace and partial fractions. The first problem involves finding L{tn} for n>0, the second problem involves finding L^{-1} (\frac{1}{s^2+k^2}), and the third problem involves splitting into partial fractions and solving for A and B.
  • #1
Patton84
2
0
I'm having some trouble getting the inverse Laplace to the following problems...I need some help

F(s)=24/s^5

F(s)= 4/[((s-2)^2)+25

F(s)= s/(s-1)(s+1)
 
Physics news on Phys.org
  • #2
For the first one, consider L{tn} works out to be for n>0.

For the second one what is

[tex]L^{-1} (\frac{1}{s^2+k^2)[/tex]

for the third one, split into partial fractions.
 
  • #3
rock.freak667 said:
For the first one, consider L{tn} works out to be for n>0.

For the second one what is

[tex]L^{-1} (\frac{1}{s^2+k^2)[/tex]

for the third one, split into partial fractions.


would this be right for the third one

A/s-1 + B/s+1 = s
 
  • #4
Patton84 said:
would this be right for the third one

A/s-1 + B/s+1 = s

Yes that's correct.
 
  • #5
djeitnstine said:
Yes that's correct.

No that is wrong, the right formula is:

[tex]\frac{s}{(s-1)(s+1)}=\frac{A}{s-1}+\frac{B}{s+1}[/tex]

from which you need to determine A and B.

coomast
 
  • #6
coomast said:
No that is wrong, the right formula is:

[tex]\frac{s}{(s-1)(s+1)}=\frac{A}{s-1}+\frac{B}{s+1}[/tex]

from which you need to determine A and B.

coomast


Oops I thought he multiplied it out and set it equal to s:rolleyes:
 

What is the "HELP" Inverse Laplace Transform?

The "HELP" Inverse Laplace Transform is a mathematical technique used in engineering and physics to find the inverse Laplace transform of a function. It stands for Heaviside Expansion of Laplace Procedure and was developed by English mathematician Oliver Heaviside.

How does the "HELP" Inverse Laplace Transform work?

The "HELP" Inverse Laplace Transform involves using a series of partial fraction expansions and a table of known Laplace transforms to find the inverse Laplace transform of a function. The technique is particularly useful for functions with repeated poles.

What are the benefits of using the "HELP" Inverse Laplace Transform?

The "HELP" Inverse Laplace Transform allows for a relatively straightforward method of finding the inverse Laplace transform of a function, even for more complex functions. It can also be used to solve differential equations and is a useful tool in control theory and signal processing.

Are there any limitations to the "HELP" Inverse Laplace Transform?

One limitation of the "HELP" Inverse Laplace Transform is that it can only be used for rational functions, meaning that the function must be a ratio of two polynomials. It also requires knowledge of the table of known Laplace transforms, which can be time-consuming to reference.

How is the "HELP" Inverse Laplace Transform used in real-world applications?

The "HELP" Inverse Laplace Transform is used extensively in engineering and physics to solve problems involving differential equations and transfer functions. It is also used in fields such as electronic circuit design, control systems, and signal processing to analyze and design systems.

Similar threads

  • Differential Equations
Replies
4
Views
1K
  • Differential Equations
Replies
17
Views
858
  • Differential Equations
Replies
1
Views
656
Replies
5
Views
2K
  • Differential Equations
Replies
6
Views
2K
  • Differential Equations
Replies
7
Views
2K
  • Differential Equations
Replies
2
Views
2K
  • Differential Equations
Replies
5
Views
4K
  • Differential Equations
Replies
1
Views
2K
  • Calculus and Beyond Homework Help
Replies
10
Views
1K
Back
Top