Using Table and Computer to find the sum of a series

In summary, the conversation discusses the use of tables and computers to find the exact sum of series in problem section 15 of chapter 1 in Mary Boas' book. One person asks about the specific type of table Boas is referring to and the possibility of using a computer to find the sum. Another person recommends using a spreadsheet and cites Gradsteyn and Ryzhik's Table of Integrals as a useful reference. The conversation also touches on the idea of convergence and the difficulty of finding the exact sum for some series.
  • #1
Seydlitz
263
4
I'm doing problem section 15 chapter 1 by Boas. I don't want to ask about a particular problem in there but she often gives this kind of instruction, "By computer or tables, find the exact sum of each of the following series." My question is, what kind of table she is referring to? I take it there must be some kind of equivalent table to integral table. I checked Wiki and there's one but it seems to be too general.

I want to find this for example, question in page 41 there's this series.

##\sum_{n=1}^{\infty} \frac{n}{(4n^2-1)^2}##

Is it possible to find the above series using a combination of elementary functions, or is that series unique? I can't find it in the wiki table.

Secondly, is it legitimate if I just put the type to WolframAlpha directly to answer the question? (Using computer method)

Thank You
 
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  • #2
Note that:
[tex]\frac{n}{(4n^{2}-1)^{2}}=\frac{n}{(2n+1)^{2}(2n-1)^{2}}[/tex]
Further partials fractions decomposition,
in seeking to rewrite this as the sum: a/(2n+1)^2+b/(2n-1)^2 might help you along.
You get, twice, that a+b=0, and -4a+4b=1, meaning be=1/8, a=-1/8
The two subseries has a nice relation between them.
 
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  • #3
arildno said:
Note that:
[tex]\frac{n}{(4n^{2}-1)^{2}}=\frac{n}{(2n+1)^{2}(2n-1)^{2}}[/tex]
Further partials fractions decomposition,
in seeking to rewrite this as the sum: a/(2n+1)^2+b/(2n-1)^2 might help you along.
You get, twice, that a+b=0, and -4a+4b=1, meaning be=1/8, a=-1/8
The two subseries has a nice relation between them.

Ok I notice you can telescope the series to get ##S_{n}=\frac{1}{8}-\frac{1}{8(2n+1)^2}## and so ##S=\frac{1}{8}##.

What I did before was to decompose ##((2n-1)(2n+1))^-1)## first and then try to get the partial sum. After that I square the partial sum and multiply it with the formula for the series of ##n##. Apparently this technique is flawed.

Is it okay though as I asked before to use computer because the question allows it? Can all convergent series be nicely decomposed like this?

Edit: And oh another thing, why don't you reduce the power of the denominator of the partial fraction? They have a power of 2. Is it okay not to add additional term because all of the denominators have the same power?
 
  • #4
You don't need to use terms like a/(2n+1), because it is sufficient with the square terms.
Meaning that if you DO get the correct expressions with a/(2n+1), then these can be recast into the simplified square form I gave.
 
  • #5
"Can all convergent series be nicely decomposed like this?"
If God wills it, perhaps. If he exists at all, something I doubt. :smile:
 
  • #6
When Mary Boas wrote her book, software like Mathematica was just a fantasy. When she says to use a computer, I'm sure she meant to write a routine which calculates the terms of the series and produces partial sums until some cutoff criteria was met. Today, we would use a spreadsheet to do such a calculation.

Gradsteyn And Ryzhik include tables of various series in their Table of Integrals:

http://atsol.fis.ucv.cl/dariop/site...ralov_Summ_Rjadov_I_Proizvedennij_Engl._2.pdf

This is a handy reference to have. (And yes, your example series is printed in this book along with its sum.)
 
  • #7
arildno said:
"Can all convergent series be nicely decomposed like this?"
If God wills it, perhaps. If he exists at all, something I doubt. :smile:

I just looked at the table SteamKing gave, most of the series there have nice sum. Are those obtained by the application computer or have they existed for long already, calculated analytically?

SteamKing said:
When Mary Boas wrote her book, software like Mathematica was just a fantasy. When she says to use a computer, I'm sure she meant to write a routine which calculates the terms of the series and produces partial sums until some cutoff criteria was met. Today, we would use a spreadsheet to do such a calculation.

Gradsteyn And Ryzhik include tables of various series in their Table of Integrals:

http://atsol.fis.ucv.cl/dariop/site...ralov_Summ_Rjadov_I_Proizvedennij_Engl._2.pdf

This is a handy reference to have. (And yes, your example series is printed in this book along with its sum.)

Thanks there! I'm very impressed with the book and it's completeness. :D

Considering when the Boas book was printed, is the reason why I asked this question. It just seems weird trying to use WA with old books like this. She did say "find the exact sum" though.

So how do I best approach this problem then in your opinion to get the most out of it?
 
  • #8
What about most series, which does not appear in those tables?
Do you think they have nice, tidy sums as well?
Or is it, perhaps, the other way around:
Those series with nicy, tidy sums end up in tables, all the others don't?
 
  • #9
arildno said:
What about most series, which does not appear in those tables?
Do you think they have nice, tidy sums as well?
Or is it, perhaps, the other way around:
Those series with nicy, tidy sums end up in tables, all the others don't?

Right I got it, but those tidy series, are they obtained by computer or analytically? If the latter then are there any standard sum methods out there? Or does each series has its own unique method in order to find its sum. For instance ##\sum 1/n^2## turns out to be ##\frac{\pi}{6}## through rather advanced algebra. I'm asking this because most of the discussion related to series seem to be focused on determining whether one is convergent or not, and not about finding its sum.
 
  • #10
No, there is no one single, general method to do this. And those formulas you see are ALL analytical expressions.
Computers cannot tell you whether that expression, or one diverging with a trillionth in its value from the expression is correct. at least not yet, they can't. And it should be pi^2/6, not pi/6


And yes:
Convergence whether divergence IS the critical issue; it is no point in setting a computer to calculate the sum of a divergent series, is there?
But, it might be very useful, once you've established convergence, to let the computer spit out a value YOU know ought to lie "close" to the actual sum neither you or the computer ever will know.
 
  • #11
I think if you examine the particular series from your example, you will see that for the first half dozen terms or so, the denominator gets rather large rather quickly, while the numerator is only increasing incrementally. Therefore, it would be reasonable to conclude on first examination that this particular series should converge rather rapidly.

Now obviously, one could use some clever algebra to manipulate this series into some simpler ones, which could be evaluated directly. But by doing successive partial sums, I think one could deduce the limiting sum rather more quickly.
 

What is the purpose of using a table and computer to find the sum of a series?

The purpose of using a table and computer to find the sum of a series is to efficiently and accurately calculate the sum of a large number of terms. This method eliminates the potential for human error and saves time compared to manually adding up each term.

What are the basic steps for using a table and computer to find the sum of a series?

The basic steps for using a table and computer to find the sum of a series are:

  • Enter the values of each term in the series into a table
  • Create a formula or function in the computer program to add up all the terms
  • Apply the formula to the table to calculate the sum
  • Double check for any errors or mistakes

What type of series can be solved using a table and computer?

A table and computer can be used to find the sum of any type of series, whether it is arithmetic, geometric, or a combination of both. As long as the series has a pattern or formula, it can be calculated using this method.

How accurate are the results when using a table and computer to find the sum of a series?

The accuracy of the results depends on the precision of the values entered into the table and the accuracy of the formula used. As long as there are no errors or mistakes, the results should be very accurate.

Can a table and computer be used for series with an infinite number of terms?

Yes, a table and computer can be used to find the sum of a series with an infinite number of terms. However, the accuracy of the results may be limited by the precision of the computer's calculations. In these cases, it is important to use more advanced methods to calculate the sum.

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