Register to reply

Magnetization and magnetic susceptibility

Share this thread:
smantics
#1
Nov17-13, 02:50 PM
P: 12
For magnetization which can be written as [itex]\vec{B}[/itex] = μ(o) ([itex]\vec{H}[/itex] + [itex]\vec{M}[/itex]) , how would it be expressed as a function of N (number density N atoms per unit volume), μ , magnetic-field Bo, T, and some constants (Boltzman's constant, Curie constant)? I have found similar set ups from different sources, but I am unsure which I should use. What I have come up with so far is (some of these are equivalent to others):

B/t = ( [itex]\frac{K(b)}{μ}[/itex]) tanh-1([itex]\frac{M(z)}{N*μ}[/itex])

M = μ tanh ( [itex]\frac{μ*B(effective)}{K(b) * T}[/itex] )

M(z) ≈ [itex]\frac{N*μ^2*B}{K(b)*T}[/itex] = [itex]\frac{n*μ(b)^2 * H}{K(b) * T}[/itex]

M = N * μ * L([itex]\frac{μ * H}{K * T}[/itex] )


Then to find the low-field magnetic susceptibility which is [itex]\vec{M}[/itex] = xm * [itex]\vec{H}[/itex] should I use:

xm = [itex]\frac{N*μ^2*B(o)*H}{K(b)*T}[/itex]

xm = [itex]\frac{μ(o)}{V}[/itex] * [itex]\frac{∂M}{∂H}[/itex]

xm = [itex]\frac{N}{V}[/itex] * [itex]\frac{μ(o)*μ(b)^2}{K(b)*T}[/itex]

xm = [itex]\frac{C}{T}[/itex]

xm = μ(o)*μ(b)^2*g(E(f))


I feel like the 3rd equation for the Magnetization would be the correct one to use, and the 1st equation for the magnetic susceptibility would be the correct one to use.
Phys.Org News Partner Physics news on Phys.org
Engineers develop new sensor to detect tiny individual nanoparticles
Tiny particles have big potential in debate over nuclear proliferation
Ray tracing and beyond

Register to reply

Related Discussions
Magnetic field of a cylinder with magnetization M=ks^2 Advanced Physics Homework 1
Magnetization of a material with linear susceptibility Classical Physics 6
Magnetic anisotropy - easy directions of magnetization Advanced Physics Homework 0
Magnetization of magnetic Introductory Physics Homework 2
Magnetic susceptibility Atomic, Solid State, Comp. Physics 2