What is the concentration of the Ba(OH)2 solution in mol/L?

[briteliner]

Homework Statement

suppose that for a 10 mL sample of Ba(OH)2 solution, the mass of the cubicle with precipitate is 17.539g and the mass of the empty cubicle is 17.410g. calculate the concentration of the Ba(OH)2 solution from this data.

Homework Equations

The Attempt at a Solution

 

[abelanger]

You can find the molar mass of Ba(OH)2 with the periodic table, the change in mass of the crucible is the mass of the Ba(OH)2, which means you can find the # of moles of Ba(OH)2 you got. And finally you know that concentration is mole per liter.

 

[Blueshift5]

To calculate the concentration of the Ba(OH)2 solution, we need to first find the mass of the precipitate. This can be done by subtracting the mass of the empty cubicle (17.410g) from the mass of the cubicle with precipitate (17.539g). This gives us a mass of 0.129g for the precipitate.

Next, we need to determine the molar mass of Ba(OH)2, which is 171.34 g/mol. Using the molar mass and the mass of the precipitate, we can calculate the number of moles of Ba(OH)2 present in the sample.

Number of moles = mass / molar mass
Number of moles = 0.129g / 171.34 g/mol
Number of moles = 0.000753 mol

Finally, we can use the volume of the sample (10 mL) to calculate the concentration of the solution.

Concentration = number of moles / volume
Concentration = 0.000753 mol / 0.010 L
Concentration = 0.0753 mol/L

Therefore, the concentration of the Ba(OH)2 solution is 0.0753 mol/L. This means that for every liter of the solution, there are 0.0753 moles of Ba(OH)2 present.