- #1
Rajini
- 621
- 4
Hello all,
I need to know the area under the following curve (Lorentzian type):
[tex]f(x)=\frac{I(\Gamma/2) ^2}{(x-x_0)+(\Gamma/2) ^2}=\frac{I\Gamma ^2}{4(x-x_0)+\Gamma ^2}[/tex].
In the above Loretzian function we all know that [tex]\Gamma[/tex] is fullwidth at half maximum, [tex]x_0[/tex] is peak's centre and [tex]I[/tex] is the height.
What is the area under Lorentzian function shown above (for [tex]x_0=0[/tex])?
[tex]\int f(x)=?[/tex].
please help me!
thanks
I need to know the area under the following curve (Lorentzian type):
[tex]f(x)=\frac{I(\Gamma/2) ^2}{(x-x_0)+(\Gamma/2) ^2}=\frac{I\Gamma ^2}{4(x-x_0)+\Gamma ^2}[/tex].
In the above Loretzian function we all know that [tex]\Gamma[/tex] is fullwidth at half maximum, [tex]x_0[/tex] is peak's centre and [tex]I[/tex] is the height.
What is the area under Lorentzian function shown above (for [tex]x_0=0[/tex])?
[tex]\int f(x)=?[/tex].
please help me!
thanks