Calculate Unbalanced Force to Stop a Car in 3 Seconds

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In summary, a car with a mass of 1350 kg and an initial speed of 21 m/s came to a halt in 3 seconds. The magnitude of the unbalanced force applied to the brakes was calculated to be 9450 N in the opposite direction of the velocity. The value of Newtons should be written as a positive magnitude without the negative sign.
  • #1
zoezoehzoe
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Homework Statement



A car has a mass of 1350 kg and an initial speed of 21 m s-1. Calculate the magnitude of the unbalanced force applied to the brakes that caused the car to come to a halt in 3 seconds.

Homework Equations



Force = mass x acceleration,
= ( 1350 kg ) x ( -7 m s-2 ),
= -9450 kg m s-2
= -9450 N

My question is this, is it ok to write the answer as a negative value of Newtons, as above, because it doesn't seem right? I'm a little confused, any advice would be appreciated.

The Attempt at a Solution

 
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  • #2
zoezoehzoe said:
My question is this, is it ok to write the answer as a negative value of Newtons, as above, because it doesn't seem right? I'm a little confused, any advice would be appreciated.
Magnitudes are always positive. In this case, the negative sign just indicates the direction--that the acceleration and force were opposite to the velocity.
 
  • #3
Doc Al said:
Magnitudes are always positive. In this case, the negative sign just indicates the direction--that the acceleration and force were opposite to the velocity.

so

Force = mass x acceleration,
= ( 1350 kg ) x ( -7 m s-2 ),
= -9450 kg m s-2
= 9450 N

would be correct?
 
  • #4
Yes. Your answer would just be the magnitude--leave off any sign.
 
  • #5
Doc Al said:
Yes. Your answer would just be the magnitude--leave off any sign.

thank you very much for your help.
 

1. How do you calculate unbalanced force to stop a car in 3 seconds?

The formula for calculating unbalanced force to stop a car in 3 seconds is F = m x a, where F is the unbalanced force, m is the mass of the car, and a is the acceleration. To find the acceleration, divide the change in velocity by the change in time (in this case, the change in velocity is the initial velocity, since the car needs to come to a complete stop). This will give you the force needed to stop the car in 3 seconds.

2. What units are used to measure unbalanced force?

The SI unit for unbalanced force is Newtons (N). However, other commonly used units include pounds (lbs) and kilograms (kg).

3. How does the mass of the car affect the unbalanced force needed to stop it?

The mass of the car directly affects the unbalanced force needed to stop it. The greater the mass of the car, the greater the force needed to stop it in the same amount of time. This is because a heavier car has more inertia, meaning it resists changes in its motion and requires a greater force to overcome it.

4. Is the unbalanced force the only factor that determines how quickly a car can be stopped?

No, there are other factors that can affect how quickly a car can be stopped, such as the braking system, road conditions, and the driver's reaction time. The unbalanced force is just one component of the overall stopping process.

5. Can the unbalanced force needed to stop a car in 3 seconds be reduced?

Yes, the unbalanced force needed to stop a car in 3 seconds can be reduced by either decreasing the mass of the car or increasing the time it takes to come to a stop. This can be achieved by using brakes with a lower force, increasing the distance between the car and the object it is stopping at, or increasing the time it takes to apply the brakes.

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