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By using the following formulation of the thermoelectric effect:
[tex]\mathbf{j} = \mathbf{\L}_{11}\mathbf{\xi} + \mathbf{\L}_{12}(-\mathbf{\nabla}T)[/tex]
[tex]\mathbf{j} = \mathbf{\L}_{21}\mathbf{\xi} + \mathbf{\L}_{22}(-\mathbf{\nabla}T)[/tex]
where [tex]\mathbf{\L}_{ij}[/tex] are tensors that charaterizes a given material.
What would be the easiest conceivable experiment to measure [tex]\mathbf{\L}_{ij}[/tex] of a certain material. One cannot exploit the Seebeck effect to get the ABSOLUTE VALUES of the coefficients of ONE METAL, since when you connect the leads of a voltmeter on the metal, it creates a temperature gradient inside of the meter itself (which would lead to false data). On the other hand, the use of the Peltier and Thomson effect leads to certain problems. I'm pretty sure that I must use one these effects to measure these coefficients, but I'm not sure how to do it .
[tex]\mathbf{j} = \mathbf{\L}_{11}\mathbf{\xi} + \mathbf{\L}_{12}(-\mathbf{\nabla}T)[/tex]
[tex]\mathbf{j} = \mathbf{\L}_{21}\mathbf{\xi} + \mathbf{\L}_{22}(-\mathbf{\nabla}T)[/tex]
where [tex]\mathbf{\L}_{ij}[/tex] are tensors that charaterizes a given material.
What would be the easiest conceivable experiment to measure [tex]\mathbf{\L}_{ij}[/tex] of a certain material. One cannot exploit the Seebeck effect to get the ABSOLUTE VALUES of the coefficients of ONE METAL, since when you connect the leads of a voltmeter on the metal, it creates a temperature gradient inside of the meter itself (which would lead to false data). On the other hand, the use of the Peltier and Thomson effect leads to certain problems. I'm pretty sure that I must use one these effects to measure these coefficients, but I'm not sure how to do it .
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