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jti3066
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Homework Statement
A ball of mass m is launched at an angle theta from a spring gun of length D. The lower end of the gun, where the spring is attatched, is at ground level. The spring has spring constant k and an unstretched length D. Before launch, the spring is compressed to a length d.
Determine the maximum height h above the ground the ball reaches.
Homework Equations
(k(x^2)/2)=mgh
?? x = mgcos(theta)
The Attempt at a Solution
Plugging in "x" I get: h=(k(mgcos(theta))^2)/2mg
Is this correct? If not please explain in detail and provide the steps and solution. TIA.