X-Ray diffraction - The Von Laue's equation

shayaan_musta

Hello experts!

I have some questions related to the X-Ray Diffraction using Laue's treatment.

I have attached some images. I have marked in red what I want to ask.

Kindly tell me where did these equations come? Is there any low level physics included too, if so then kindly guide me through.



How do you write PA as r.n[itex]_{o}[/itex]?
Where does it come, ∅[itex]_{r}[/itex]=[itex]\frac{2π}{λ}[/itex](r.N). I know this is path difference. But where does the (r.N) come?



How path difference become equal to 2πh[itex]^{'}[/itex]=2πnh
and,
How aNcosα=2asinθcosα ?
and similarly,
How 2asinθcosα=h[itex]^{'}[/itex]λ=nhλ

Thank you all.

vatlychatran

Hi, with only high-school knowledge you can answer your questions. PA=OP.cos(PA,OP)=OP.PA/PA.cos(PA,OP)=OP.n₀
[itex]\phi[/itex]_r is phase difference, not path difference
[itex]\phi[/itex]_r=wavevector×pathdifference
wavevector=2π/λ

shayaan_musta

Thank you for answer. I am sorry, I lost my connection therefore I have late in reply. So can you answer this one too?