- #1
jamesd2008
- 64
- 0
Hi could someone explain why this result occurs when solving this differential equation.
dx/dt= xt
1/xdx/dt=t then intergrating both side we get with respect to dt we get,
Inx=t^2/2 + c now this is the bit i don't understand why does the answer then become,
x=Ce^2/t^2
I get really confused how the equation gets re-arranged into the above form after the intergration has occured. Any help please?
Thanks
James
dx/dt= xt
1/xdx/dt=t then intergrating both side we get with respect to dt we get,
Inx=t^2/2 + c now this is the bit i don't understand why does the answer then become,
x=Ce^2/t^2
I get really confused how the equation gets re-arranged into the above form after the intergration has occured. Any help please?
Thanks
James