- #1
preet
- 98
- 0
I'm a little confused here. I have a function: f(x) = x^2 + 3
If the domain of the function is
-3 <= x <= 3
I need to find the range...
I think that the answer is 3 <= y <= 12... that can be found out by drawing the graph. But I want to find the range algebraically. It says in my textbook to turn the 'x' in the middle of the domain shown above into the respective f(x) equation (x^2)+3... and performing whatever action on x on the other sides of the inequality. This works in other functions, but I think I'm doing something wrong with this one:
1.-3 <= x <= 3
2.9 <= x^2 <= 9
3.12 <= x^2 + 3 <= 12
I think that because in step 1 I multiplied one value by (-3) I need to flip the greater than/equal to sign(s), but not sure how to do it... as you can see, by step 3, the wrong answer is reached. Can anyone show me my mistake? Thanks!
If the domain of the function is
-3 <= x <= 3
I need to find the range...
I think that the answer is 3 <= y <= 12... that can be found out by drawing the graph. But I want to find the range algebraically. It says in my textbook to turn the 'x' in the middle of the domain shown above into the respective f(x) equation (x^2)+3... and performing whatever action on x on the other sides of the inequality. This works in other functions, but I think I'm doing something wrong with this one:
1.-3 <= x <= 3
2.9 <= x^2 <= 9
3.12 <= x^2 + 3 <= 12
I think that because in step 1 I multiplied one value by (-3) I need to flip the greater than/equal to sign(s), but not sure how to do it... as you can see, by step 3, the wrong answer is reached. Can anyone show me my mistake? Thanks!