
#1
Feb514, 11:36 AM

P: 38

Is this equation equal to:
(e^(hf/kT))  1 or e^( (hf/kT)  1 ) http://s29.postimg.org/le6iqy3rb/exp.png 



#2
Feb514, 11:46 AM

P: 206

The former.




#3
Feb514, 12:05 PM

Mentor
P: 20,971

The image in the link is [exp(hf/kT)  1]. What you have written is ambiguous, as what you probably meant is this: $$e^{\frac{hf}{kT}  1}$$ What you actually wrote, though, is this: $$e^{\frac{hf}{k}T  1}$$ The brackets  []  around the entire expression are unnecessary. 



#4
Feb514, 01:47 PM

Sci Advisor
PF Gold
P: 1,111

Simple mathematical problemMy guess is that Mechatron did not write that himself, but saw it in a book. It's most probably related to the Planck distribution (blackbody radiation). As economicsnerd said, the correct reading is $$ e^{\beta h f}  1 \mbox{ where } \beta = \frac{1}{kT} $$ The additional bracket [] might be there because it is part of a greater equation. 



#5
Feb1514, 09:58 AM

P: 4

Im sorry to be off topic but I'm using a i device and i can't see (what i think to be) mathematical symbols that are in this thread... They appear as dollar signs and other randoms, i was wondering if maybe I'm short of additional download or setting adjustments. All help is highly appreciated




#6
Feb1514, 11:00 AM

Mentor
P: 20,971

(e^(hf/kT))  1 and e^( (hf/kT)  1 ) In any case, this is moot, as Mechatron has been banned from PF. 


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