Is Richard Robinett's Fourier Transform Convention Unconventional?

In summary, there is a difference in sign convention for the Fourier transform and inverse Fourier transform as defined by Richard Robinett and others. However, this sign difference is not significant as it only affects the constants in front and does not alter the fundamental meaning or applications of the transform. Both conventions are valid and widely used in physics literature.
  • #1
ehrenfest
2,020
1

Homework Statement


Richard Robinett defined the Fourier transform with an exp(-ikx) and the inverse Fourier transform with an exp(ikx). I have always seen the opposite convention and I thought it was not even a convention but a necessity to do it the other in order to apply it to some Gaussian equations. Has anyone ever seen this sign convention before?




Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
  • #2
It really isn't relevant whether it's with a plus, or with a minus. I've seen in most cases

[tex]\phi (x)=\frac{1}{(2\pi)^{3/2}}\int dk \ \tilde{\phi}(k) e^{-ikx} [/tex].
 
  • #3
Note that the integration is from [itex]-\infty[/itex] to [itex]\infty[/itex]. That's why the sign does not matter.
 
  • #4
Furthermore, the constants in front also do not really matter, as long as they combine to give 1/(2 pi). There are a couple of theorems which depend on them (I think Parseval's theorem and the associated ones do), but it's all up to a constant. My supervisor (in physics) recommends just ignoring the constants, and adding them back in if you have to at the end :wink:
 
  • #5
If you define the Fourier transform as dextercioby did:
[tex]\phi (x)=\frac{1}{(2\pi)^{3/2}}\int dk \phi(k) e^{-ikx}[/tex]
then the inverse transform is:
[tex]\phi (k)=\frac{1}{(2\pi)^{3/2}}\int dx \phi(x) e^{ikx}[/tex]
It is merely a matter of convention which is called which. There's no 'wrong' convention as long as you remain consistent.

On page 11 of 'Photons and Atoms' by Claude Cohen-Tannoudji et. al. the convention above is used. On page 97 of 'The Principles of QM' by P.A.M. Dirac, the convention is left deliciously ambiguous.
Dirac said:
These formulas have elementary significance. They show that either of the representations is given, apart from numerical coefficients, by the amplitudes of the Fourier components of the other.
 
Last edited:

1. What is Robinett's Fourier transform?

Robinett's Fourier transform is a mathematical tool used in signal processing and analysis to decompose a complex signal into its constituent frequencies. It is a modification of the traditional Fourier transform that takes into account the non-periodic nature of many real-world signals.

2. How is Robinett's Fourier transform different from the traditional Fourier transform?

Unlike the traditional Fourier transform, which is only applicable to periodic signals, Robinett's Fourier transform can be used for non-periodic signals. It also allows for a more accurate representation of signals with sharp edges or discontinuities.

3. What are the applications of Robinett's Fourier transform?

Robinett's Fourier transform has various applications, including image and audio processing, data compression, and filtering in communication systems. It is also used in physics, particularly in quantum mechanics, to analyze wave functions and energy states.

4. What is the mathematical formula for Robinett's Fourier transform?

The mathematical formula for Robinett's Fourier transform is similar to the traditional Fourier transform, but with an additional factor of e^(-jwx) included in the integral. This term accounts for the non-periodic nature of the signal and allows for a more accurate representation of its frequencies.

5. Are there any limitations to using Robinett's Fourier transform?

One limitation of Robinett's Fourier transform is that it requires the signal to be time-limited, meaning that it only exists for a finite period of time. It also assumes that the signal is continuous, which may not always be the case in real-world applications. Additionally, some signals may be too complex for Robinett's Fourier transform to accurately represent their frequencies.

Similar threads

  • Advanced Physics Homework Help
Replies
17
Views
2K
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Advanced Physics Homework Help
Replies
4
Views
2K
Replies
3
Views
998
Replies
4
Views
4K
  • Advanced Physics Homework Help
Replies
4
Views
2K
  • Advanced Physics Homework Help
Replies
2
Views
3K
  • Advanced Physics Homework Help
Replies
4
Views
3K
  • Advanced Physics Homework Help
Replies
2
Views
1K
  • Advanced Physics Homework Help
Replies
16
Views
4K
Back
Top