- #1
pizat98
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I have been working at this question for a while. I have to find the frictional force and the coefficient of friction. skier has a mass of 64kg, starts at top of a 18 degree slope and let's gravity take her downhill. slope is 65 m long and her speed is 15 m/s when she get to the bottom. how do I find the x component of weight as well? The answer for coefficient is 0.14N according to the book and frictional force is 83N.
Fnet=mg
fk=ukFn
I came up with Fn=605N in relation to the y axis. a=3.03 m/s^2 (alteast what I got)
I have tried a thousand different ways to do this and I keep getting myself more confused. The number I keep coming up with for coeff is .32 and I don't have a clue about frictional force. Any help would be great.
Fnet=mg
fk=ukFn
I came up with Fn=605N in relation to the y axis. a=3.03 m/s^2 (alteast what I got)
I have tried a thousand different ways to do this and I keep getting myself more confused. The number I keep coming up with for coeff is .32 and I don't have a clue about frictional force. Any help would be great.