Rate will this student burn calories

[lalahelp]

rate will this student "burn" calories

Homework Statement

A student wants to lose some weight. He knows that rigorous aerobic activity uses about 700 kcal/h (2900 kJ/h) and that it takes about 2000 kcal per day (8400 kJ) just to support necessary biological functions, including keeping the body warm. He decides to burn calories faster simply by sitting naked in a 12.5° C room and letting his body radiate calories away. His body has a surface area of about 1.7 m2 and his skin temperature is 35° C. Assuming an emissivity of 1.0, at what rate will this student "burn" calories?

Homework Equations

dQ/dt=h.A.dT
1*1.7*295.5
=502.35 J/s

Why is my answer wrong?

 

[marcoskids]

Is T not 288.5K ?

 

[marcoskids]

Is T not 288.5K ?

Sorry 285.5K

 

[lalahelp]

Yes your right but even with that I still get the wrong answer

 

[asteriatic]

Your answer is incorrect because you have not taken into account the conversion from Joules to calories. The correct equation to use for this problem is Q = m.c.(Tf-Ti), where Q is the amount of energy in calories, m is the mass of the student, c is the specific heat capacity of the body, Tf is the final temperature (12.5°C in this case), and Ti is the initial temperature (35°C in this case).
Once you have calculated the amount of energy (in calories) that the student's body will lose per second, you can divide by 3600 (the number of seconds in an hour) to determine the rate at which he will burn calories. This will give you a more accurate answer.
Additionally, it is important to note that this method of weight loss is not safe or effective. The body needs a certain amount of energy (calories) to function properly, and drastically reducing calorie intake or trying to burn them off through extreme methods can have negative consequences on overall health. It is always best to consult with a healthcare professional before making any significant changes to your diet or exercise routine.