Exploring the Domain and Range, X-Intercept, and Vertical Asymptote of y=logx^4

In summary, the given equation is y=logx4 and the domain is x>0, while the range is all real numbers. The x-intercept is (1,0) and the vertical asymptote is x=1.
  • #1
Erin_Sharpe
17
0
y=logx4
state domain and range, x-intercept, vertical asymptote.

I have never seen a question like this before.

Please help me!
 
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  • #2
It might be easier to find what you're after by the rewriting:
[tex]x^{y}=4[/tex]
 
  • #3
Note that since for real exponents, the exponential is only defined for positive numbers, so the maximal domain for x is x>0.
Try and find out the range and where a vertical asymptote must be!
 
  • #4
HINT:It may be much easier if u rewrote it:
[tex] y(x)=\frac{\ln 4}{\ln x} [/tex]

Daniel.
 
  • #5
Oops!
x=1 must be excluded from the domain!
 
  • #6
:( this is so sad. because I completely don't understand this at all. it just makes absolutely no sense to me... is there any way it could be explained to me any easier?
 
  • #7
vertical asymptote... 4? :s
 
  • #8
What's the definition of a vertical asymptote...?

Daniel.
 
  • #9
Erin sharpe:
Do you understand the transformation:
[tex]y=log_{x}4\to{x}^{y}=4\to{y}=\frac{ln(4)}{ln(x)}[/tex]
(the last step was given by Daniel)
 

1. What is the domain of the function y=logx^4?

The domain of the function y=logx^4 is all positive real numbers, since the logarithm function is only defined for positive inputs. In other words, x must be greater than 0 for the function to be defined.

2. How do you find the range of y=logx^4?

The range of y=logx^4 is all real numbers, since the logarithm function can output any real number depending on the input. However, the output of y=logx^4 will always be positive, since x^4 will always be positive regardless of the value of x.

3. What is the x-intercept of y=logx^4?

The x-intercept of y=logx^4 is (1,0). This is because any number raised to the power of 0 is equal to 1, so when x=1, the function will output 0.

4. How do you determine the vertical asymptote of y=logx^4?

The vertical asymptote of y=logx^4 is x=0. This is because as x approaches 0 from the positive side, the output of the function approaches negative infinity. However, the function is not defined for negative inputs, so there is no vertical asymptote on the negative side.

5. Can the function y=logx^4 have a horizontal asymptote?

No, the function y=logx^4 does not have a horizontal asymptote. As x approaches infinity, the output of the function will continue to increase without bound, so there is no horizontal line that the graph will approach.

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