- #1
prasannapakkiam
Okay. If hot Potassium PERMANGANATE (KMnO4-) with concentrated acid, is added to Ethene, what will form.
If I look at my textbook, I can deduce that first the alkene would oxidise into a di-diol. Then the bond splits, then;
a hydrogen would get replaced by an oxygen
otherwise, the OH would get replaced by an oxygen.
If I follow this pattern for Ethene, I think 2 Methanoic Acids should be formed, instead 2 Carbon Dioxides are formed according to my textbook!
So what are the products?
Also can someone give me a link or some information about the mechanism involved here.
If I look at my textbook, I can deduce that first the alkene would oxidise into a di-diol. Then the bond splits, then;
a hydrogen would get replaced by an oxygen
otherwise, the OH would get replaced by an oxygen.
If I follow this pattern for Ethene, I think 2 Methanoic Acids should be formed, instead 2 Carbon Dioxides are formed according to my textbook!
So what are the products?
Also can someone give me a link or some information about the mechanism involved here.