Electronic Devices byfloyd Problem

[extreme2000]

Dear users
In question i have to find the filter capacitor "C" value i have ripple factor given circut
is full wave rectifier circut R(L) is given V(out) of the rectifier is 18V I have calculated the V(peak)(rectified voltage) but in the following formula
Vr(Peak to Peak) =(1/f*R(L)C)*Vp(Rectified)
frequency is also known
I have done what
calculated the V(Rectified Volatge)all other things are also known but two things are missing in above equation the Vr(Peak to Peak) if this is know by any means I can then calculate the value of Filter capacitor C any help? I have to submit the assingment tomorrow
Thanks

 

[Nate810]

The formula you have is correct and you have all the necessary parameters except for Vr(Peak to Peak). You need to determine this value in order to find the value of C. To do this, you can look up the ripple factor of your full wave rectifier circuit and use that to calculate Vr(Peak to Peak) using the following formula: Vr(Peak to Peak) = Vp(Rectified)* Ripple Factor. Once you have this value, you can plug it into the original equation to solve for C.

 

[ogb p]

Dear user,

Thank you for your question. It seems like you are working on a project or assignment related to electronic devices and specifically a full wave rectifier circuit. In order to calculate the value of the filter capacitor "C", you need to know the peak-to-peak voltage, which is represented by Vr(Peak to Peak) in the formula you mentioned.

To find the peak-to-peak voltage, you can use the following formula:

Vr(Peak to Peak) = V(peak) * 2

Where V(peak) is the peak voltage you have already calculated. Once you have the value for Vr(Peak to Peak), you can plug it into the formula you mentioned and solve for the value of the filter capacitor "C".

I hope this helps. Good luck with your assignment!