UV & Irradiance: Calculating UVA Dose for High School Project

In summary, the individual is seeking help with calculating irradiance and UV dose for a biology project involving drosophila m. (fruit flies) and UVA radiation. They provide formulas for calculating irradiance and ask for clarification on the variables involved. They also share information on the lamp being used for the experiment. The expert advises that the provided information is not enough to accurately calculate irradiance and suggests considering the emitted power in the desired wavelength range and the geometry of the lighting situation. They also mention the importance of taking into account any optical elements that may affect the amount of flux reaching the sample.
  • #1
hopeariipus
1
0
Dear forum members,

I would like to ask some help regarding irradiance calculation. I am a high school student doing a project in biology in which I expose drosophila m. (fruit flies) to UVA radiation and I would like to mention in my paper the actual dose that was used.

I know that... UV dose (J/m^2) = W/m^2 x s

W/m^2 refers to irradiance, this is the formula that I found for calculating it:

E= dΦ / d Ad

1. Ad is the area which is exposed to the radiation.
What does the d in front of Ad stand for?

dΦ = E0 cosθ d Ad

So, the formula above is the radiation intensity (W)...

2. E0 is the irradiance of light incident upon material, how do I calculate that?

From here I found the information: http://metrology.hut.fi/courses/S-108.4110/2007/RADIOMETRIA.pdf (on the 5th page)

Lamp:

Original Philips UVA
Type HP3147/A
220V ~ 50 Hz 75W


Thank you for any advice and help!
 
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  • #2
W/m2 means energy over a certain surface ( which in the case of a fruit fly is less than 1.5 mm2 )

Energy is computed by power and distance ( from source to target) with the illusive reflectivity taking it's tole.
 
  • #3
hopeariipus said:
<snip>

I know that... UV dose (J/m^2) = W/m^2 x s

W/m^2 refers to irradiance, this is the formula that I found for calculating it:

E= dΦ / d Ad

1. Ad is the area which is exposed to the radiation.
What does the d in front of Ad stand for?

dΦ = E0 cosθ d Ad

The first formula is the definition of irradiance (also emittance and excitance), where 'Φ' is the flux and Ad is the projected area- loosely speaking, the amount of area that is perpendicular to the flux. That's where the 'cosθ' term comes from in the second formula- a flat surface perpendicular to the flux has the same projected area, but a surface parallel to the flux has zero projected area. The extra 'd's indicate the expression is in terms of differential areas (which is important if the surface is curved, for example).

hopeariipus said:
<snip>
Lamp:

Original Philips UVA
Type HP3147/A
220V ~ 50 Hz 75W

Thank you for any advice and help!

This is not sufficient information to calculate the irradiance. It's not enough to know the power of the bulb, one must know the *emitted* power in the waveband of interest and the geometry of the lighting situation. Phillips (or Osram, another manufacturer) can tell you how much light (in your waveband of interest) the bulb gives off, but you need to know what the projected area of your sample is.

Another wrinkle- if your source is a fluorescent bulb (long and thin, not like a short arc or an incandescent), and if there are optical elements that refract or reflect some of the light toward your sample, you need to first calculate how much flux is passing through your sample plane. The rough calculation is fairly simple- what fraction of the total output is directed at your sample is usually sufficient- and if the illumination is fairly uniform, that simplifies the calculation even more.

Hope this helps...
 
  • #4
So, if I want to calculate the UV-B irradiance, I need to consider the sum the irradiance from 290-315 nm?
 
  • #5


Dear high school student,

It's great to see that you are conducting a project on UVA radiation and its effects on drosophila m. (fruit flies). Calculating the UVA dose is an important aspect of your research and I can provide some guidance on how to do so.

Firstly, let's define some terms to have a better understanding of the calculations involved. Irradiance is the amount of power per unit area of a surface, typically measured in watts per square meter (W/m^2). UVA dose is the amount of UVA radiation received by a surface, measured in joules per square meter (J/m^2).

To calculate the UVA dose, you will need to know the irradiance of the UVA radiation being used and the duration of exposure. As you mentioned, the formula for calculating UVA dose is UV dose (J/m^2) = W/m^2 x s, where s is the duration of exposure in seconds. So, you will need to measure the irradiance of your UVA lamp and multiply it by the duration of exposure to get the UVA dose in joules per square meter.

Now, let's address your questions about the formula for calculating irradiance. The "d" in front of Ad stands for differential, which means that the formula is looking at the change in area (d Ad) over a small interval. This is important because the irradiance may not be uniform across the entire area being exposed to the UVA radiation.

To calculate E0, the irradiance of the light incident upon the material, you will need to measure the power of the UVA lamp (in watts) and divide it by the area of the lamp's surface that is emitting the radiation. In this case, it would be the area of the lamp's surface facing the drosophila m. (fruit flies). You can use a light meter or a radiometer to measure the power of the lamp.

I hope this helps you in calculating the UVA dose for your project. Remember to always follow safety precautions when working with UVA radiation and consult with a teacher or mentor if you have any further questions. Good luck with your project!
 

1. What is UVA radiation and how does it differ from other types of UV radiation?

UVA radiation is a type of ultraviolet (UV) radiation that falls within the range of 315-400 nanometers on the electromagnetic spectrum. It differs from other types of UV radiation, such as UVB and UVC, in its longer wavelength and ability to penetrate deeper into the skin.

2. Why is it important to calculate UVA dose for a high school project?

Calculating UVA dose is important for a high school project because it allows students to understand the potential effects of UVA radiation on living organisms. It also gives students a hands-on opportunity to learn about scientific methods and data analysis.

3. What factors are involved in calculating UVA dose?

The factors involved in calculating UVA dose include the intensity of UVA radiation, the duration of exposure, and the sensitivity of the organism to UVA radiation. Other factors, such as the use of sunscreen or protective clothing, may also impact the UVA dose received.

4. How do you measure UVA radiation and convert it into a UVA dose?

UVA radiation can be measured using a UV meter or a spectrophotometer. These instruments can provide readings in units of watts per square meter (W/m²). To convert this measurement into a UVA dose, the W/m² value is multiplied by the duration of exposure in seconds. The resulting value is then divided by 1000 to obtain the UVA dose in joules per square meter (J/m²).

5. What are some potential applications of calculating UVA dose in a high school project?

Some potential applications of calculating UVA dose in a high school project include studying the effects of UVA radiation on different types of organisms, exploring the effectiveness of different sun protection methods, and investigating the relationship between UVA exposure and skin cancer risk. It can also be used to educate students about the importance of sun safety and the potential dangers of excessive UVA exposure.

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