- #1
Wingeer
- 76
- 0
Homework Statement
Given the function:
[tex]f(x)=\left\{
\begin{array}{cl}
x+2x^2\sin\left(\frac{1}{x}\right), & x\neq 0 \\
0, & x=0
\end{array}\right.[/tex]
& [tex] f'(0)=1[/tex]
"Show that all intervals containing x=0, will also have a point where f'(x) < 0. (This shows that even if f'(0) > 0, f is not increasing on any interval containing x=0"
Homework Equations
Well, this is part b of a problem. Part a was to find f'(0)=1, which I did by the mean-value theorem.
The Attempt at a Solution
If I could just get a hint on how to solve this, part b, I will attempt a solution.