Introducing LaTeX Math Typesetting

[robphy]

Use \displaystyle

$$dt = \frac{da}{H_0 \left(\displaystyle\frac{\Omega_{m,0}}{a} + a^2 \Omega_{\Lambda,0}\right)^{\frac{1}{2}}}$$

 

[dextercioby]

Yikes,i guess I'm still a rookie...

Daniel.

 

[bomba923]

$$\begin{array}{l} Would{\rm }it{\rm }be{\rm }O.K{\rm }to{\rm }write{\rm }complete{\rm }posts{\rm }in{\rm }LaTex, \\ without{\rm }math{\rm }in{\rm }them \ldots {\rm }just{\rm }writing? \\ \end{array}$$

NOt that I can---but what if ?

 

[hellfire]

Use \displaystyle

Thank you!

 

[richnfg]

$$v = 0.13$$

$$P = \frac{1}{f}$$

 

[richnfg]

$$/mean=\frac{\sum x}{n}$$

 

[robphy]

$$\begin{array}{l} Would{\rm }it{\rm }be{\rm }O.K{\rm }to{\rm }write{\rm }complete{\rm }posts{\rm }in{\rm }LaTex, \\ without{\rm }math{\rm }in{\rm }them \ldots {\rm }just{\rm }writing? \\ \end{array}$$

NOt that I can---but what if ?

You probably wanted to put the extra backslash to escape the space {\rm\ } to get
$$\begin{array}{l} Would{\rm\ }it{\rm\ }be{\rm\ }O.K{\rm\ }to{\rm\ }write{\rm\ }complete{\rm\ }posts{\rm\ }in{\rm\ }LaTex, \\ without{\rm\ }math{\rm\ }in{\rm\ }them \ldots {\rm\ }just{\rm\ }writing? \\ \end{array}$$

You could just write it in an mbox
$$\mbox{ Would it be O.K to write complete posts in \LaTeX, \\ without math in them \[\ldots\] just writing? }$$
or in a verbatim environment
$$\begin{verbatim} Would it be O.K to write complete posts in LaTeX, without math in them... just writing? \end{verbatim}$$

However, I think it is probably discouraged to post like this.

 

[bomba923]

The quadratic formula:

$$\begin{gathered} ax^2 + bx + c = 0,\\ x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }} {{2a}} \hfill \\ \end{gathered}$$

 

[bomba923]

Brachistochrone Equation:
$${\left\{ \begin{gathered} x = r\left( {\theta - \sin \theta } \right) \hfill \\ y = r\left( {1 - \cos \theta } \right) \hfill \\ \end{gathered} \right\}}$$

 

[OlderDan]

Whenever you want to include a graphic on the same line with your text, like $C H_4$ or $G_\textrm{diffeo}$ or $y = mx + b$, you should use [ itex ]...[ /itex ] instead of [ tex ]...[ /tex ]. The "i" means "inline."

Click on each of the examples above to "learn by example."

If you have questions or comments about this site addition, you are welcome to post them here!

Good luck, and enjoy the system.

- Warren

I came looking specifically because my "inlines" were not in line. Glad to find this, but even with the itex the graphic is still raised. Is there a trick for lowering it more if you want to?

Edit

I am on a different machine now, and things look different. The inline text here does look inline. It is some local setting on my computer making the difference.

 

[twoflower]

$$blablablah \\ newlineblabla$$

Why doesn't \\ insert a new line for me?

 

[Starship]

Problems with brackets:

$$\left(\begin{array}{cc}\frac{\partial u}{\partial x}&\frac{\partial \nu}{\partial x}\\ \frac{\partial \nu}{\partial x}&\frac{\partial u}{\partial x}\end{array}\right)$$

$$\phi(x,y)$$

$$\frac{\partial^2 \phi}{\partial u^2} + \frac{\partial^2 \phi}{\partial \nu^2} = 0$$

$$w = u(x,y) + i\nu(x,y)$$

$$\frac{\partial \phi}{\partial x} = \frac{\partial \phi}{\partial u} \frac{\partial u}{\partial x} + \frac{\partial \phi}{\partial \nu} \frac{\partial \nu}{\partial x}$$

and

$$\frac{\partial \phi}{\partial y} = \frac{\partial \phi}{\partial u} \frac{\partial u}{\partial y} + \frac{\partial \phi}{\partial \nu} \frac{\partial \nu}{\partial y}$$

A second differentiation of these yields the results:

$$\frac{\partial^2 \phi}{\partial x^2} = \frac{\partial \phi}{\partial u} \frac{\partial^2 u}{\partial x^2} + \left ( \frac{\partial^2 \phi}{\partial u^2} \frac{\partial u}{\partial x} + \frac{\partial^2 \phi}{\partial \nu \partial u} \frac{\partial \nu}{\partial x} \right ) \frac{\partial u}{\partial x} + \frac{\partial \phi}{\partial \nu} \frac{\partial^2 \nu}{\partial x^2} + \left ( \frac{\partial^2 \phi}{\partial u \partial \nu} \frac{\partial u}{\partial x} + \frac{\partial^2 \phi}{\partial \nu} \frac{\partial \nu}{\partial x} \right ) \frac{\partial \nu}{\partial x}$$

Adding:

$$\frac{\partial^2 \phi}{\partial x^2} + \frac{\partial^2 \phi}{\partial y^2} = \frac{\partial \phi}{\partial u} \left ( \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} \right ) + \frac{\partial^2 \phi}{\partial u^2} \left [ \left ( \frac{\partial u}{\partial x} \right )^2 + \left ( \frac{\partial u}{\partial y} \right )^2 \right ] + 2 \frac{\partial^2 \phi}{\partial u \partial \nu} \left ( \frac{\partial u}{\partial x} \frac{\partial \nu}{\partial y} \right ) + \frac{\partial \phi}{\partial \nu} \left ( \frac{\partial^2 \nu}{\partial x^2} + \frac{\partial^2 \nu}{\partial y^2} \right ) + \frac{\partial^2 \phi}{\partial \nu^2} \left [ \left ( \frac{\partial \nu}{\partial x} \right )^2 + \left ( \frac{\partial \nu}{\partial y} \right )^2 \right ]$$

$$w = u + i\nu$$

$$\frac{\partial^2 \phi}{\partial x^2} + \frac{\partial^2 \phi}{\partial y^2} = \frac{\partial^2 \phi}{\partial u^2} \left [ \left ( \frac{\partial \nu}{\partial x} \right )^2 + \left ( -\frac{\partial \nu}{\partial x} \right )^2 \right ] + \frac{\partial^2 \phi}{\partial \nu^2} \left [ \left ( \frac{\partial \nu}{\partial x} \right )^2 + \left ( \frac{\partial u}{\partial x} \right )^2 \right ] = \left [ \left ( \frac{\partial u}{\partial x} \right )^2 + \left ( \frac{\partial \nu}{\partial x} \right )^2 \right ] \left ( \frac{\partial^2 \phi}{\partial u^2} + \frac{\partial^2 \phi}{\partial \nu} \right ) = |f'(z)|^2 \left ( \frac{\partial^2 \phi}{\partial u^2} + \frac{\partial^2 \phi}{\partial \nu^2} \right )$$

 

[bomba923]

Just redefining an earlier problem I had (Do NOT pay attention to this! )

$${\text{Let}} f_n \left( t \right) = \left\{ \begin{gathered} x_n \left( t \right) \hfill \\ y_n \left( t \right) \hfill \\ z_n \left( t \right) \hfill \\ \end{gathered} \right\} , {\text{ }} {\text{continuous}} {\text{ }} \forall t \in \left( {a,b} \right)$$

At any moment $t \in \left( {a,b} \right)$, a triangle can be defined by the set of points $\left\{ {f_1 \left( t \right),f_2 \left( t \right),f_3 \left( t \right)} \right\}$.
Find the exact volume generated by this triangle from $t = a$ to $t = b$.

(Don't pay attention to this)

 

[Moo Of Doom]

$$a\xrightarrow{c}b$$

I can display things on top of arrows, but is it possible to display text under them (preferrably both above and below at the same time, actually)?

 

[robphy]

$$a \stackrel{c}{\longrightarrow} b$$


$$a \overset{c}{\longrightarrow} b$$

$$a \underset{d}{\longrightarrow} b$$

$$a \underset{d}{\overset{c}{\longrightarrow}} b$$

 

[Moo Of Doom]

Thankesy! :)

 

[Dr.Brain]

$\sum \int \bigodot$

 

[extreme_machinations]

$$F=GmM_e/r^2$$

Edit: You added an unnecessary "\" before the F and G, and left out the necessary "/" in your second bracket.

 

[extreme_machinations]

$$a^x_n$$ ...

Edit: You left spaces in your brackets.

 

[extreme_machinations]

hey how come i can't get it to work ??

 

[Doc Al]

hey how come i can't get it to work ??

See my edits of your posts.

 

[nu_paradigm]

$$\int_{0}^{\frac{\pi}{2}} \log \cos \kappa d \kappa$$

 

[nu_paradigm]

Just trying...

$$\int_{0}^{\frac{\pi}{2}} \log \cos \Omega \ d \Omega$$

$$f(x) = \sin x, \mbox{if} \ x \ \epsilon \ (0, \frac{\pi}{2})$$

 

[nu_paradigm]

$$f(x) = \left {\begin{array}{cc}\sin x,&\mbox{if} \ x \epsilon \ [0, \frac{\pi}{2})\\ \cos x, & \mbox{if} \ x \epsilon \ [\frac{\pi}{2}, \pi)\end {array}\right$$

 

[extreme_machinations]

$$F=GmM_e/r^2$$

 

[extreme_machinations]

aaahhaa! now that more like it
hey thanks doc

 

[extreme_machinations]

$$f(x)=sinx^2$$

 

[extreme_machinations]

$$int_{0}^{1} sinlogx$$

 

[extreme_machinations]

$$\int_{0}^{1} sin^2logcosx dx$$

 

[saltydog]

This is a test

$$\begin{array}{1|c|c|c|c|c|} \text{Fixed Point}&\text{Jacobian}&\text{Eigenvalues}&\text{Eigenvectors}&\text{type}\\ \hline (0,0)& \left(\begin{array}{cc}1.5 & 0 \\ 0 & 2 \end{array}\right)& 2,1.5 & \left(\begin{array}{ca}0 \\ 1 \end{array}\right) \left(\begin{array}{ca}1 \\ 0 \end{array}\right)& \text{Source}\\ \hline (0,2)& \left(\begin{array}{cc}0.5 & 0 \\ -1.5 & -2 \end{array}\right)& -2,0.5 & \left(\begin{array}{ca}0 \\ 1 \end{array}\right) \left(\begin{array}{ca}0.86 \\ -0.51 \end{array}\right)& \text{Saddle}\\ \hline (1.5,0)& \left(\begin{array}{cc}-1.5 & -0.75 \\ 0 & 0.88 \end{array}\right)& -1.5,0.88 & \left(\begin{array}{ca}1 \\ 0 \end{array}\right) \left(\begin{array}{ca}-0.3 \\ 0.95 \end{array}\right)& \text{Saddle}\\ \hline (4/5,7/5)& \left(\begin{array}{cc}-0.8 & -0.4 \\ -1.05 & -1.4 \end{array}\right)& -1.8,-0.38 & \left(\begin{array}{ca}0.37 \\ 0.93 \end{array}\right) \left(\begin{array}{ca}0.69 \\ -0.72 \end{array}\right)& \text{Sink}\\ \hline \end{array}$$

Slick!

 

[dextercioby]

$$\int_{0}^{1} sin^2logcosx dx$$

Doesn't look good.This one does.

$$\int_{0}^{1} \sin^{2}x \ln\cos x \ dx$$


Daniel.

 

[lawtonfogle]

please help, i cannot find the 'does not equal' latex equation

 

[dextercioby]

\neq should do it.

Daniel.

 

[lawtonfogle]

$$a \neq b$$

this should work

 

[lawtonfogle]

next question, can i download this for my computer, i have a paper due when i return to school, and it will be a vast help to be able to type the symbols.