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jcvince17
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induced emf in secondary coil - help ASAP Please
A very long, straight solenoid with a cross-sectional area of 6.00 cm2 is wound with 40.0 turns of wire per centimeter, and the windings carry a current of 0.250 A. A secondary winding of 2.00 turns encircles the solenoid at its center. When the primary circuit is opened, the magnetic field of the solenoid becomes zero in 5.00×10−2 s .
What is the average induced emf in the secondary coil?
E = Delta flux / delta time
flux = BA cos Theta
B = U0*n*I
I have no idea where to begin. to find the flux I need the Magnetic Field. I do not know the magnetic field value so How can I find flux to in turn find E?
Please get me started correctly.
I think I have found B on the first coil.
B = U0*n*I
B = U0*240*0.250A I used 240 as it is 40 turns per cm.
B = 7.54*10-5 ?
then if i fund flux of coil 1 =
flux = BA
fulx = 7.54*10-5 * .0006 m2 = 4.53*10-8 ?
i tried doing the same for the other coil, but I do not have anything to get area of that coil.
i used:
N1/N2 = I1/I2 for I2 and got I2 = .0125A ?
Homework Statement
A very long, straight solenoid with a cross-sectional area of 6.00 cm2 is wound with 40.0 turns of wire per centimeter, and the windings carry a current of 0.250 A. A secondary winding of 2.00 turns encircles the solenoid at its center. When the primary circuit is opened, the magnetic field of the solenoid becomes zero in 5.00×10−2 s .
What is the average induced emf in the secondary coil?
Homework Equations
E = Delta flux / delta time
flux = BA cos Theta
B = U0*n*I
The Attempt at a Solution
I have no idea where to begin. to find the flux I need the Magnetic Field. I do not know the magnetic field value so How can I find flux to in turn find E?
Please get me started correctly.
I think I have found B on the first coil.
B = U0*n*I
B = U0*240*0.250A I used 240 as it is 40 turns per cm.
B = 7.54*10-5 ?
then if i fund flux of coil 1 =
flux = BA
fulx = 7.54*10-5 * .0006 m2 = 4.53*10-8 ?
i tried doing the same for the other coil, but I do not have anything to get area of that coil.
i used:
N1/N2 = I1/I2 for I2 and got I2 = .0125A ?
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