Shaking the Atom: Electron Shells & Nucleus Resonance

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In summary, the nucleus of an atom has a positive charge and is surrounded by negatively charged electron shells. When electromagnetic radiation is shined onto the atom, there is a potential for movement of the nucleus and electron shell together, resulting in observable changes in the atom. This movement can be described using the classical two-body problem and the effective potential energy of the atom. Overall, this is a classical explanation for atomic transitions, with the only overlooked factor being the angular momentum carried by the photon.
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warabi
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The nucleus has positive charge, with negative electron shell(s) around it. The nucleus is located in the center of the electron shell. Electrical forces keep it there.

Now what if we shine electromagnetic radiation (linearly polarised) onto an atom? With the E-field going "up", will the nucleus have a tendency to move "up", with the electron shell wanting to move "down"? Will there be a resonant frequency in which a relatively large amount of electromagnetic energy is absorbed from the incoming radiation, and the relative movement between nucleus and shell is maximised? In other words could there be movement of the electron shell "as a whole", not e.g. excitation of individual electrons, and could it be observable?
 
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A two-body problem is equivalent to a problem of a particle with reduced mass:

[tex]
\frac{1}{m} = \frac{1}{m_{1}} + \frac{1}{m_{2}}
[/tex]

in the center-of-mass frame. For hydrogen atom, this would be the Coulomb potential. Due to conservation of angular momentum [itex]\mathbf{L}[/itex], the motion may be further reduced to the radial direction (one-dimensional) in an effective potential energy:

[tex]
V_{l}(r) = \frac{L^{2}}{2 m r^{2}} - \frac{k_{0} e^{2}}{r}
[/tex]

This "effective" potential energy has a local minimum:

[tex]
V_{l}'(r) = -\frac{L^{2}}{m r^{3}} + \frac{k_{0} e^{2}}{r^{2}} = 0
[/tex]

[tex]
r_{0} = \frac{L^{2}}{m k_{0} e^{2}}
[/tex]

[tex]
V_{l}''(r) = \frac{3 L^{2}}{m r^{4}} - \frac{2 k_{0} e^{2}}{r^{3}} = \frac{m^{3} (k_{0} e^{2})^{4}}{L^{6}} \equiv k > 0
[/tex]

Around this local minimum, the effective potential energy may be expanded into Taylor series:

[tex]
V_{l}(r) = V_{l}(r_{0}) + \frac{1}{2} k (r - r_{0})^{2}
[/tex]

i.e. it looks like a harmonic oscillator. The oscillation frequency is:

[tex]
\omega = \sqrt{\frac{k}{m}} = \frac{m (k_{0} e^{2})^{2}}{L^{3}}
[/tex]

If one uses [itex]L \sim \hbar[/itex], one gets that this oscillation frequency is the same as the transition frequency emitted or absorbed in the Bohr model, up to numerical factors. So, what you had described is actually the classical picture of atomic transitions. The only important feature we had neglected is that the photon carries angular momentum, so the angular momentum of the atom during such transitions is not conserved.
 

1. What is "Shaking the Atom" and why is it important?

"Shaking the Atom" refers to the process of using energy to excite the electrons in an atom, causing them to move to higher energy levels. This is important because it allows scientists to study the structure and behavior of atoms, and has led to many advancements in fields such as chemistry and physics.

2. What are electron shells and how do they relate to "Shaking the Atom"?

Electron shells are the energy levels that electrons occupy in an atom. When an atom is "shaken", the electrons can move to higher energy levels, creating new electron shells. This allows scientists to study the different energy levels and their corresponding properties.

3. What is nucleus resonance and how does it play a role in "Shaking the Atom"?

Nucleus resonance refers to the vibration or movement of the nucleus of an atom. When the atom is "shaken" and the electrons are excited, the nucleus may also vibrate or move, leading to changes in the atom's overall energy. This can provide valuable information about the atom's structure and behavior.

4. How is "Shaking the Atom" used in practical applications?

"Shaking the Atom" has many practical applications, including in fields such as medical imaging, materials science, and energy production. By understanding the behavior of atoms and their energy levels, scientists can develop new technologies and improve existing ones.

5. Are there any potential risks or concerns associated with "Shaking the Atom"?

There are potential risks associated with "Shaking the Atom", such as accidentally causing damage to the atom or creating unstable or radioactive particles. However, these risks are carefully monitored and controlled in scientific experiments, and the benefits of studying atoms far outweigh any potential risks.

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