- #1
nomisme
- 29
- 0
HI,
please help me... I am thirsty for any insights to my problem.
I have a motor:
Output: 60W
VOLT:12V DC
AMP: 7.5A
RPM:1800
TORQUE: 3.5kgcm
I have a motor reducer:
for converting rotation movement of motor to up and down motion(for lifting heavy load)
look like this http://www.yhcdsb.com/Eweb/uploadfile/20120405235504775.jpg
It has a speed reduction ratio of 12:1.
Based on theory, if I have a 3.5kgcm input torque to the motor reducer,I will get 3.5kgcm x 12= 42kgcm from the motor reducer. It means that I will have no difficulties in lifting loads less than 30kg without damaging the motor, right?
The problem is I tried both AC and DC motors. Both of them have difficulties lifting the 30kg loads and generate high heat which cause the motors to slowly die out.
I have checked the circuitry and no problem was found on the power supply.
I am really confused about the gear ratio stuff... I get my speed reduced by a factor of 12. Does it mean that my torque is multiplied by a factor of 12 too? It seems not to be the case. Does the efficiency of the motor reducer places an important part on it? how significant is it?
please help me... I am thirsty for any insights to my problem.
I have a motor:
Output: 60W
VOLT:12V DC
AMP: 7.5A
RPM:1800
TORQUE: 3.5kgcm
I have a motor reducer:
for converting rotation movement of motor to up and down motion(for lifting heavy load)
look like this http://www.yhcdsb.com/Eweb/uploadfile/20120405235504775.jpg
It has a speed reduction ratio of 12:1.
Based on theory, if I have a 3.5kgcm input torque to the motor reducer,I will get 3.5kgcm x 12= 42kgcm from the motor reducer. It means that I will have no difficulties in lifting loads less than 30kg without damaging the motor, right?
The problem is I tried both AC and DC motors. Both of them have difficulties lifting the 30kg loads and generate high heat which cause the motors to slowly die out.
I have checked the circuitry and no problem was found on the power supply.
I am really confused about the gear ratio stuff... I get my speed reduced by a factor of 12. Does it mean that my torque is multiplied by a factor of 12 too? It seems not to be the case. Does the efficiency of the motor reducer places an important part on it? how significant is it?
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