Register to reply 
Complex numbers 
Share this thread: 
#1
Jun914, 06:24 PM

P: 129

I just wanted to check something. If I have a complex number of the form
[itex]a = C * \exp(i \phi) [/itex] where C is some noncomplex scalar constant. Then the phase of this complex number is simply [itex]\phi[/itex]. Is that correct? 


#2
Jun914, 06:49 PM

Sci Advisor
HW Helper
PF Gold
P: 3,289

If ##C < 0##, then you need to absorb the sign of ##C## into the phase: $$a = C\exp(i \phi) = C\exp(i(\phi + \pi))$$ If ##C = 0## then the phase is undefined. 


#3
Jun1014, 01:09 AM

P: 129

Thank you for this detailed answer!



Register to reply 
Related Discussions  
All real numbers are complex numbers?And are I #'s orthogonal R#'s?  General Math  7  
Strange real numbers requiring use of complex numbers to exist  General Math  7  
Splitcomplex numbers and dual numbers  General Math  1  
Complex numbers representing Real numbers  General Math  3  
Complex numbers  are they the 'ultimate', or are there any complex complex numbers  Calculus  7 