How would shell theorem act in a hollow sphere?

In summary, the shell theorem states that the force of gravity is focused at the center of an object. But, say that there is a large planet with a gravitational force equal to that of earth's. It is perfectly round… and hollow. Since it is hollow, how large would it be to have Earth's gravity? Stranger yet, what would the effects be inside and outside of the sphere?
  • #1
Joseph King
29
0
What I understand is this: Shell theorem states that the force of gravity is focused at the center of an object. But, say that there is a large planet with a gravitational force equal to that of earth's. It is perfectly round… and hollow. Since it is hollow, how large would it be to have Earth's gravity? Stranger yet, what would the effects be inside and outside of the sphere?
 
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  • #2
To have Earth gravity what would be its mass?

What is the gravity inside any shell of a given mass?

How large the planet is depends on the size of the shell and the density of mass composing it, right?
 
  • #3
Exactly. And what effects would it have on other objects inside the sphere.
 
  • #4
There are two shell theorems that describe the field from a spherically symmetry shell of mass. One describes the field outside the shell, the other describes the field inside the shell. Are you familiar with both of those?
 
  • #5
I only know of the one focused inward.
 
  • #6
Joseph King said:
I only know of the one focused inward.
And what does that theorem say? (In post #1 you mentioned the theorem that deals with the field outside the shell.)
 
  • #7
Well, basically, it states that if you have an object (ie earth) then the force of gravity is focused at the center. So, if you are underground, the mass above you does not have any gravitational effect on you.
 
  • #8
Joseph King said:
Well, basically, it states that if you have an object (ie earth) then the force of gravity is focused at the center. So, if you are underground, the mass above you does not have any gravitational effect on you.
Here's how I would put the two theorems:

(1) Outside the shell, the field is that of a point mass equal to the mass of the shell and located at the center of the shell.

(2) Inside the shell, the field is everywhere zero.
 
  • #9
That makes sense, thanks!
 

1. What is the Shell Theorem?

The Shell Theorem states that the gravitational force exerted by a spherical shell on a point mass outside of the shell is the same as if all the mass of the shell was concentrated at its center. This means that the gravitational force inside a hollow sphere is zero.

2. How does the Shell Theorem apply to a hollow sphere?

The Shell Theorem applies to a hollow sphere in that it states that the gravitational force inside the sphere is zero. This is because the mass of the sphere is distributed evenly throughout the shell, resulting in the gravitational forces from each part of the shell cancelling each other out.

3. What is the significance of the Shell Theorem?

The Shell Theorem is significant because it allows for simplified calculations of gravitational forces in situations where a spherical object's mass is distributed evenly throughout its surface. It also helps us understand the behavior of gravity in large-scale systems such as planets and stars.

4. Does the Shell Theorem only apply to hollow spheres?

No, the Shell Theorem also applies to solid spheres. However, the gravitational force inside a solid sphere is not zero, as there is mass present at every point inside the sphere. The Shell Theorem states that the force is the same as if all the mass were concentrated at the center, but it is not zero.

5. How does the Shell Theorem relate to Newton's Law of Universal Gravitation?

The Shell Theorem is a consequence of Newton's Law of Universal Gravitation. It is a mathematical result that can be derived from the Law of Universal Gravitation and the geometry of a spherical object. The Shell Theorem is a useful tool for applying the Law of Universal Gravitation to specific situations, such as a hollow sphere.

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