Solving the Mystery of Drop Out Ride: Find Rev/s Needed for Floor Drop Out

In summary, the problem involves a ride called Drop Out where riders are spun in horizontal circles of radius 5.5m. The floor drops out when the ride achieves a certain angular velocity, and the coefficient of static friction is 0.28. The problem can be solved by setting up a free body diagram and using the equation for centripetal acceleration, a=v^2/r, to relate the normal force and frictional force. The unknown angular velocity can then be solved for.
  • #1
habs.fan
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Homework Statement


In a ride called Drop Out, riders are spun in horizontal circles of radius 5.5m, which forces them to the outer wall. When they are spinning fast enough, the floor drops out, and they are suspended by friction. The coefficient of static friction is 0.28, how many rev/s must the ride achieve before the floor is allowed to drop out?


Homework Equations


a[tex]_{}c[/tex] = rv^2


The Attempt at a Solution


I'm sort of lost for what to do, I have an FBD with G (down) and Friction (up), I also know the centripetal acceleration will be along the radius, towards the center of the circle, but I do not know how to solve this one.
Thanks in advance.
 
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  • #2
No, a=v^2/r. If you know the centripetal acceleration, then you know the normal force. You then can relate the frictional force to the normal force, et voila. Please continue.
 
  • #3
ok so...ac = v^2/5.5
v is unknown though, so we don't really know the centripetal acceleration?
 
  • #4
You know the radius, and v can be expressed in terms of the angular velocity. Leave it unknown. That's what you want to solve for.
 

1. How do you determine the necessary rev/s for a floor drop out ride?

The rev/s needed for a floor drop out ride can be determined by first calculating the distance between each drop out, and then dividing that distance by the total time of the ride. This will give you the rev/s needed to ensure each drop out occurs at the correct time.

2. What factors can affect the necessary rev/s for a floor drop out ride?

The necessary rev/s for a floor drop out ride can be affected by several factors, such as the distance between drop outs, the weight of the riders, and the speed of the ride. Additionally, factors such as wind resistance and friction can also impact the rev/s needed for a smooth and consistent ride experience.

3. Why is it important to find the correct rev/s for a floor drop out ride?

Finding the correct rev/s for a floor drop out ride is important because it ensures that each drop out occurs at the designated time, providing a safe and enjoyable ride experience for riders. If the rev/s is too low, the ride may be too slow and not provide enough excitement. If the rev/s is too high, the ride may be too fast and potentially dangerous.

4. Can computer simulations be used to determine the necessary rev/s for a floor drop out ride?

Yes, computer simulations can be used to determine the necessary rev/s for a floor drop out ride. By inputting the ride's specifications and variables, such as speed, weight, and distance between drop outs, the simulation can calculate the optimal rev/s for a safe and enjoyable ride experience.

5. Are there any safety precautions to consider when determining the necessary rev/s for a floor drop out ride?

Yes, safety precautions should always be taken into consideration when determining the necessary rev/s for a floor drop out ride. These may include testing the ride at different rev/s to ensure it can safely handle the speed and weight of riders, as well as regularly maintaining and inspecting the ride to ensure it is in proper working condition.

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