Projectile fired at an angle from 1m

In summary, a projectile is fired upward at an angle with an initial speed of 15.0 m/s and from a height of 1.00m. If its speed at the top of its arc is 7.5 m/s, the projectile reaches a height of 9.6m. To find the speed at which it hits the ground, use kinematics to determine the final vertical velocity at impact. This can be calculated by using the horizontal component of the velocity (7.5 m/s) and the Pythagorean Theorem. The angle of projection and vertical component of the initial velocity can also be found using this information. At the top of the arc, the velocity is 0 m/s. To find the
  • #1
celcon
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0
a projectile is fired upward at an angle, with a speed of 15.0 m/s and from a height of 1.00m. A) if its speed to the top of its arc is 7.5 m/s, what height does it reach? B) what is the speed with which it hits the ground?


I figured the part A to be 9.6m but I am lost on how to figure the speed at which it hits the ground.

Thanks in advance
 
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  • #2
Use kinematics to find the final vertical velocity of the projectile (Vf^2 = Vi^2 + 2gy) at impact. Use this result, and the horizontal component of the velocity = 7.5 m/s, in the Pythagorean Theorem to determine the resultant final velocity.
 
  • #3
Initial velocity Vi = 15 m/s. At the top of the arc the velocity is horizontal and is equal = Vcos(theta) = 7.5 m/s. From this find the angle of projection and vertical component of the Vi. When it reaches the top of arc Vf = 0. Now using kinematics find h. Don't forget add the initial height.
In part B, the disoplace of the projectile is - 1m. So find the final velocity when it reaches the ground. Its direction is vertical. Hence find the resultant of this velocity and horizontal component to get the final result.
 

1. What is a projectile fired at an angle from 1m?

A projectile fired at an angle from 1m refers to an object that is launched from a height of 1 meter at a certain angle with respect to the ground, and moves through the air under the influence of gravity.

2. What factors affect the trajectory of a projectile fired at an angle from 1m?

The trajectory of a projectile fired at an angle from 1m is affected by three main factors: the initial velocity of the projectile, the angle at which it is fired, and the force of gravity.

3. How is the range of a projectile fired at an angle from 1m calculated?

The range of a projectile fired at an angle from 1m can be calculated using the formula R = (v2sin2θ)/g, where R is the range, v is the initial velocity, θ is the firing angle, and g is the acceleration due to gravity.

4. Can the initial velocity of a projectile fired at an angle from 1m affect its maximum height?

Yes, the initial velocity of a projectile fired at an angle from 1m directly affects its maximum height. The greater the initial velocity, the higher the maximum height will be.

5. How does air resistance impact the motion of a projectile fired at an angle from 1m?

Air resistance can affect the motion of a projectile fired at an angle from 1m by slowing it down and altering its trajectory. However, for most practical purposes, the effect of air resistance on a projectile fired at 1m is negligible.

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