Please verify my answers, I have shown work

[snipaj9696]

A hungry bear weighing 750 N walks out on a beam in an attempt to retrieve a basket of food hanging at the end of the beam. The beam is uniform, weighs 200 N, and is 5.80 m long; the basket weighs 80.0 N.

picture is at this link http://answerboard.cramster.com/physics-topic-5-146405-0.aspx

(a) Draw a free-body diagram for the beam. (Do this on paper. Your instructor may ask you to turn in this sketch.)

(b) When the bear is at x = 1.10 m, find the tension in the wire and the components of the force exerted by the wall on the left end of the beam.

0-(750)(1.10)-(200)(2.90)-(80)(5.80)+Tsin60(5.80)=0 so T=372.1 N

Fx=(372.1)cos60=186.05 N
Fy=1030-(372.1)sin60=707.75

372.1 N (tension)
186.05 N ( Fx)
707.45 N ( Fy)

(c) If the wire can withstand a maximum tension of 750 N, what is the maximum distance the bear can walk before the wire breaks?

T=750

(750)(sin60)(5.80)-(750)Xmax-(200)(2.90)-(80)(5.80)=0 solve for Xmax

Xmax=3.868 m

Are my answeres correct? I only have once chance to enter in my answer for webassign.

Thankyou

 

[anathema]

I cannot confirm the accuracy of your calculations without more information and context. However, your approach seems reasonable and your calculations appear to be correct based on the information provided. I would recommend double checking your work and making sure that all units are consistent before submitting your answer. Also, keep in mind that the maximum distance the bear can walk before the wire breaks may be slightly different depending on the precision of your calculations. Good luck!

 

[ogb p]

for your question. I cannot verify your answers as I do not have access to the picture or the specific instructions given by your instructor. However, your calculations and approach seem correct. It is always a good idea to double check your work and make sure your units are consistent. Good luck on your assignment!