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seb26
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Homework Statement
A jet is flying horizontally from A to B. When the plane is directly overhead at B, a person on the ground (C) hears the sound coming from A. ABC is a right triangle in B. The angle BCA = 36 degrees.
The average temperature is 20 degrees Celsius. If the speed of the plane at A is 170 m/s, what is the speed at B, assuming that it has constant acceleration?
Homework Equations
f=1/T f: frequency; T: period
v= λ*f = λ/T λ: wavelength
fobserver= fplane*((v+vo)/(v+vp)) v=343m/s
The Attempt at a Solution
First off I don't see what steps to take to come up with the answer. There must some implicit data to take into consideration but I can't figure it out.
What I assume, since there is a right triangle with an angle given, is that one distance has to be found (AC) to find AB with sin.
I found the acceleration by taking t=1second. I know that the sound travels at 343m/s on AC and the speed the plane has after one second on AB is found by calculating vplane= sin(36)*343= 201.6m/s so the acceleration is a= (201.6-170)/1s= 31.6m/s2
I can't figure out how to get the distance from A to C or A to B.
PS: those values are given from my homework given by the teacher, on the book the same problem has 164m/s for the speed of the plane at A, same angle. The answer for the speed at B is 239m/s