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Julia78
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I just finished an experiment where I precipitated 2.30 g of MgNH4PO4 6H20.
The gravimetric analysis of phosphorous in this experiment is based on the
precipitation of phosphorous as MgNH4PO4 . 6H2O from a solution that contains the
monohydrogen phosphate ion (HPO42- ), ammonium ions, and magnesium ions. The
balanced reaction is:
5 H2O + HPO42- + NH41+ + Mg2+ + OH1- =====> MgNH4PO4 . 6H2O I need to calculate percent yield of MgNH4PO4 . 6H2O obtained in my experiment using 10-52-10 plant food label as a guide to determine the theoretical yield of MgNH4PO4 . 6H2O.
So, the plant food contains:
10% N
52% P2O5
10% MgO
In my experiment I used 1.2 grams of 10-52-10 plant food ( + 4 grams MgSO4 7H2O) and obtained 2.30 g of MgNH4PO4 6H20
I know that % yield = actual yield/ theoretical yield x 100%
But, how do I calculate actual yield from the data I have?
So far I calculated:
air dry weight of MgNH4PO4 . 6H2O = 2.30 g
Grams of phosphorusin MgNH4PO4 6H20 = 0.290g
%P in plant food = 24.16
% P2O5 in equivalent to %P above = 55.45
% p2O5 in 10-52-10 plant food = 52
When do I do next?? Any help is greatly appreciated?
The gravimetric analysis of phosphorous in this experiment is based on the
precipitation of phosphorous as MgNH4PO4 . 6H2O from a solution that contains the
monohydrogen phosphate ion (HPO42- ), ammonium ions, and magnesium ions. The
balanced reaction is:
5 H2O + HPO42- + NH41+ + Mg2+ + OH1- =====> MgNH4PO4 . 6H2O I need to calculate percent yield of MgNH4PO4 . 6H2O obtained in my experiment using 10-52-10 plant food label as a guide to determine the theoretical yield of MgNH4PO4 . 6H2O.
So, the plant food contains:
10% N
52% P2O5
10% MgO
In my experiment I used 1.2 grams of 10-52-10 plant food ( + 4 grams MgSO4 7H2O) and obtained 2.30 g of MgNH4PO4 6H20
I know that % yield = actual yield/ theoretical yield x 100%
But, how do I calculate actual yield from the data I have?
So far I calculated:
air dry weight of MgNH4PO4 . 6H2O = 2.30 g
Grams of phosphorusin MgNH4PO4 6H20 = 0.290g
%P in plant food = 24.16
% P2O5 in equivalent to %P above = 55.45
% p2O5 in 10-52-10 plant food = 52
When do I do next?? Any help is greatly appreciated?
Last edited: