- #1
marellasunny
- 255
- 3
By the conservation of energy, P_in=P_out
So,no matter what gear ratio 'i' I choose, P_out=P_in, since the gear ratio 'i' term would get canceled at the numerator and denominator.
$$P_{eng}= ω_{eng} M_{eng}= i . ω_{out} \frac{M_{out}}{i}$$
hence P_in=P_out
But, what is the drivetrain efficiency a function of? Is it a function of gear ratio and engine speed and engine torque? Or is it a constant always?
2.And why is the drivetrain efficiency of automatic transmissions 10% lesser than manual? [source page 417:Advanced Direct Injection Combustion Engine Technologies and Development ...
edited by H Zhao]
So,no matter what gear ratio 'i' I choose, P_out=P_in, since the gear ratio 'i' term would get canceled at the numerator and denominator.
$$P_{eng}= ω_{eng} M_{eng}= i . ω_{out} \frac{M_{out}}{i}$$
hence P_in=P_out
But, what is the drivetrain efficiency a function of? Is it a function of gear ratio and engine speed and engine torque? Or is it a constant always?
2.And why is the drivetrain efficiency of automatic transmissions 10% lesser than manual? [source page 417:Advanced Direct Injection Combustion Engine Technologies and Development ...
edited by H Zhao]