- #1
sam.pat
- 6
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I have a question about Linear least squares:
In Linear least squares, For any critical point "x" it must follow the linear system:
A(Transpose) * Ax = b * A(Transpose) where x is the critical point.
But here x is an n vector, so does that mean there are as many critical points (x) as there are columns?
So in case of an quadratic polynomial : 1 + X2*t + X3*t^2 with three parameters, would we have three critical points?
|1 t1 t1^2 |
|1 t2 t2^2 |
|1 t3 t3^3 |
|1 ... ... |
|1 ... ... |
Thanks in advance
In Linear least squares, For any critical point "x" it must follow the linear system:
A(Transpose) * Ax = b * A(Transpose) where x is the critical point.
But here x is an n vector, so does that mean there are as many critical points (x) as there are columns?
So in case of an quadratic polynomial : 1 + X2*t + X3*t^2 with three parameters, would we have three critical points?
|1 t1 t1^2 |
|1 t2 t2^2 |
|1 t3 t3^3 |
|1 ... ... |
|1 ... ... |
Thanks in advance