Periods of Trigonometric Functions

In summary, the conversation discusses finding the period of two equations, one with two sine functions and one with a cosine and sine function. The first equation has a period of one cycle and the second equation has a period of 2*pi. The conversation also mentions using QBasic to graph the functions and using trigonometric relations to solve for the period. The importance of having an integer relation between frequencies for there to be a common period is also mentioned.
  • #1
mcfetridges
13
0
Here are two general questions

How would you find the period of:

sin(2Pi*t)+sin(4Pi*t)

or

cos(3t)sin(2t)

Thanks
 
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  • #2
The first is simple it is one period of the lower frequency ( the other is a simple harmonic ) . In the second did you really mean multiply or just leave out a + sign??
I do not always find the maths simple --- my fall back to this ( to get a clue ) is to graph the function. ( But not by hand ) .
I always use QBasic in which you can set up the equations and the graph in a matter of minutes .
However cos(a).cos(b) == a function of a+b and a-b so one frequency is 5 and the other 1 , so the frequency compared to either of the originals is 1.
That is, due to multiplication beats are formed between two frequencies
Since the normal wave equation is A.Sin ( 2.pi/T.t) it , means that 2.pi/T=1
so T = 2.pi
To solve these equations for T -- first compare them to the usual equation

The multiplier of t is 2.pi.f for a simple wave or 2.pi/T --- then if required use the normal trig relations for compound functions .
In cases of addition of sine waves there will only be a common period if the frequencies have an integer relation.
The same is true for multiplications . In general there may be no period at all, or maybe extremely long. For instance cos(99.t).cos(101.t) will will have a period about 50x times greater than either .
Ray.
 
  • #3
for your question! To find the period of a trigonometric function, you need to look at the coefficient of the variable inside the parentheses. For example, in sin(2Pi*t)+sin(4Pi*t), the coefficient of t is 2Pi and 4Pi respectively. The period of a sine function is 2Pi, so the period of sin(2Pi*t) is 1 and the period of sin(4Pi*t) is 1/2. To find the period of the entire function, you need to find the least common multiple of these two periods, which is 1/2. Therefore, the period of sin(2Pi*t)+sin(4Pi*t) is 1/2.

For cos(3t)sin(2t), the period of cos(3t) is 2Pi/3 and the period of sin(2t) is Pi. The least common multiple of these two periods is 2Pi, so the period of the entire function is 2Pi.

I hope this helps! Let me know if you have any further questions.
 

1. What are the main trigonometric functions?

The main trigonometric functions are sine, cosine, tangent, cotangent, secant, and cosecant.

2. What is the period of a trigonometric function?

The period of a trigonometric function is the horizontal length of one complete cycle of the function. It is the smallest value of x for which the function repeats itself.

3. How do you find the period of a trigonometric function?

To find the period of a trigonometric function, you can use the formula: period = 2π / b, where b is the coefficient of x in the function. If there is no coefficient, then the period is 2π.

4. Can the period of a trigonometric function be negative?

No, the period of a trigonometric function cannot be negative. It is always a positive value because it represents a length or distance.

5. What is the relationship between the period and the frequency of a trigonometric function?

The period and frequency of a trigonometric function are inversely related. This means that as the period increases, the frequency decreases, and vice versa. The frequency is the number of cycles of the function that occur in one unit of time, while the period is the length of one cycle of the function.

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