Calculate the Joules Required to Heat 40 Kg of Water by 20°C

[Little_Miss]

Suppose you want to heat 40 KG of water by 20 degrees C
How many joules of heat are required.

Can someone talk me through this step by step?

 

[Doc Al]

Read this: http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html

 

[Blueshift5]

Sure, let's walk through the steps to calculate the joules required to heat 40 kg of water by 20°C.

Step 1: Determine the specific heat capacity of water
The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1 kg of that substance by 1°C. The specific heat capacity of water is 4.186 joules/gram°C.

Step 2: Convert kg to grams
Since the specific heat capacity is given in joules/gram°C, we need to convert the mass of water from kg to grams. There are 1000 grams in 1 kg, so 40 kg of water is equivalent to 40,000 grams.

Step 3: Calculate the energy required to raise the temperature by 1°C
To find the energy required to raise the temperature of 1 gram of water by 1°C, we multiply the specific heat capacity (4.186 joules/gram°C) by the mass (1 gram) and the temperature change (1°C). This gives us 4.186 joules.

Step 4: Calculate the energy required to raise the temperature by 20°C
Since we want to raise the temperature of 40,000 grams of water by 20°C, we multiply the energy required to raise the temperature by 1°C (4.186 joules) by the mass (40,000 grams) and the temperature change (20°C). This gives us 4.186 x 40,000 x 20 = 3,350,400 joules.

Therefore, the joules required to heat 40 kg of water by 20°C is 3,350,400 joules.