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kliker
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Homework Statement
a resistor of 600 Ω and one of 400 Ω are connected in series and their combination is being supplied by 90 V. A voltmeter that is connected on edge of the resistor of 600 Ω shows 60 V. a) what's the internal resistance of the voltmeter.
The Attempt at a Solution
i found the real V in the resistor of 600 V which is 54 V. But the voltmeter shows 60 V. Now I don't know how is this possible
if they are in parallel could we just find the Rtot that will be Rv* Rs/(Rv+Rs) and then say I = V/R
and from this equation find the Rv? but i find false results using this method, the book says 3000 Ω