- #1
quickclick330
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Consider the solid S described below.
The base of S is a circular disk with radius 3r. Parallel cross-sections perpendicular to the base are squares.
Find the volume V of this solid.
I tried this...
A(x) = pi*r^2 = pi*(3r)^2 = pi*9r^2
V(x) = integral from 0 to 3r(pi*9r^2 dx) = pi*27r^3
Am I approaching this problem the wrong way? Thanks for the help!
The base of S is a circular disk with radius 3r. Parallel cross-sections perpendicular to the base are squares.
Find the volume V of this solid.
I tried this...
A(x) = pi*r^2 = pi*(3r)^2 = pi*9r^2
V(x) = integral from 0 to 3r(pi*9r^2 dx) = pi*27r^3
Am I approaching this problem the wrong way? Thanks for the help!