- #1
flyingdonkey21
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Two ferryboat each traveling at different constant speed start at the same instant from opposite sides of the Hudson River, one going from New York City to Jersey City and the other from Jersey City to New York City. They pass one another at a point 720 yard from New York City shore. After arriving at their respective destinations, each boat spends precisely 10 minutes at the opposite shore to change passengers before switching directions. On the return trip, the two boats meet at a point 400 yards from the Jersey shore.
What is the width of the river?
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I look at this and my intuitiom says to use two linear motion w/ constant accelaration equations and set them equal to each other. However, I look at them all and I don't see how I can do this problem without the velocities of the two boats given. If not providing me with a solution to this, can someone at least point me in the right direction? Thank you.
Boat 1
a=0
v=CONSTANT
v=0 from t1 to t1+10
Boat 2
a=0
v=CONSTANT
v=0 from t2 to t2+10
pass @ x=720 and x=(total distance-400)
flyingdonkey21
What is the width of the river?
***********************************************
I look at this and my intuitiom says to use two linear motion w/ constant accelaration equations and set them equal to each other. However, I look at them all and I don't see how I can do this problem without the velocities of the two boats given. If not providing me with a solution to this, can someone at least point me in the right direction? Thank you.
Boat 1
a=0
v=CONSTANT
v=0 from t1 to t1+10
Boat 2
a=0
v=CONSTANT
v=0 from t2 to t2+10
pass @ x=720 and x=(total distance-400)
flyingdonkey21