Understanding the Maths Behind Space Elevators

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In summary, the conversation discusses the calculation of the volume of a frustum of a cone in relation to space elevator cables. The website provides a method to find the volume using a single integral and another method by repeatedly applying the formula for the volume of a cone. The individual is seeking assistance in understanding the process.
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RooftopDuvet
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I'm doing some research on space elevators and have found a site (http://www.zadar.net/space-elevator/#transverse") which gives some insight into the maths behind the elevator cable. If you click on the link and scroll down, up, whichever direction to equation (2) and a picture of a blue trapezium the guy has found the difference in the volume of the tapering cable with what looks like volume of revolution, but I can't seem to figure out what he's done. He says that it's 'easy to show...'. Am I missing something? I could use a little help. thanks.
 
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Quick way to show this: You are dealing with finding the volume of a frustum of a cone. The volume [itex]V[/itex] of a cone is [itex]V=\frac{1}{3}Ah[/itex], where [itex]A[/itex] is the area of the base and [itex]h[/itex] is the height.

You can get the volume of the frustum illustrated in the figure by repeatedly applying the above formula and subtracting volumes, as follows:

[tex]V=V_{frustum+missing top}-V_{missing top}[/tex]

Long way to show this: You can calculate the volume with a single integral because the frustum is a surface of revolution. Find an equation for the right boundary of the figure (it's a straight line segment, so that's easy) and solve it for x. Then revolve that line segment about the y-axis and write down an expression for the differential volume. Then integrate over y, and you should get the same expression.
 

1. How does the mathematics behind space elevators work?

The mathematics behind space elevators is based on a concept called the "tethered tower." Essentially, a long cable made of strong, lightweight material is anchored to the surface of the Earth and extends into space. The cable is held taut by the centrifugal force of a counterweight at the other end, creating a stable platform for objects to travel along.

2. What are the key equations used in the mathematics behind space elevators?

The key equations used in the mathematics behind space elevators include the equation for gravitational force, the equation for centripetal force, and the equation for tension in a cable. These equations are used to calculate the necessary strength and length of the cable, as well as the speed at which objects can travel along it.

3. How does the Earth's rotation affect the mathematics behind space elevators?

The Earth's rotation is a crucial factor in the mathematics behind space elevators. The centrifugal force created by the Earth's rotation is what keeps the cable taut and stable, allowing objects to travel along it. The speed of the Earth's rotation also plays a role in determining the length and strength of the cable needed for a space elevator to function.

4. Are there any limitations or challenges in the mathematics behind space elevators?

While the concept of a space elevator is theoretically possible, there are several challenges and limitations in the mathematics behind it. These include finding a material strong enough to withstand the tension and weight of the cable, as well as the potential for collisions with other objects in space.

5. What are the potential applications of the mathematics behind space elevators?

The potential applications of space elevators include launching payloads into space at a much lower cost compared to traditional rockets, providing a means for large-scale space exploration and transportation, and potentially even serving as a space-based power source by harnessing solar energy. However, these applications are still in the theoretical stage and would require significant advancements in technology and materials.

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