- #1
Andreatn
- 8
- 0
Can somebody explain the reason why the following reasoning is wrong?
Considering a source of electromagnetic waves at rest with respect to a reference frame, plus an observer who is approaching it with speed v, he would experience a Doppler Effect.
To measure the value of this effect we can use the equation that is in every specific book: if f is the frequency issued from the source, c the speed of light, the frequency F measured by the
observer will be: F = ( 1 – v / c ) f
that is the same as F = [ ( c – v ) / c ] f
Because the observer is moving in the opposite direction to light propagation, we must calculate as
follow: F = { [ c – ( - v ) ] / c } f
and F = [ ( c + v ) / c ]f
if the speed of light is the same for all the observers, than c + v = c
hence: F = ( c / c ) f
and: F = f
thus, the observer who is approaching the source could not verify a Doppler Effect, but the experience shows that this is not true.
Considering a source of electromagnetic waves at rest with respect to a reference frame, plus an observer who is approaching it with speed v, he would experience a Doppler Effect.
To measure the value of this effect we can use the equation that is in every specific book: if f is the frequency issued from the source, c the speed of light, the frequency F measured by the
observer will be: F = ( 1 – v / c ) f
that is the same as F = [ ( c – v ) / c ] f
Because the observer is moving in the opposite direction to light propagation, we must calculate as
follow: F = { [ c – ( - v ) ] / c } f
and F = [ ( c + v ) / c ]f
if the speed of light is the same for all the observers, than c + v = c
hence: F = ( c / c ) f
and: F = f
thus, the observer who is approaching the source could not verify a Doppler Effect, but the experience shows that this is not true.