- #1
ColdFusion85
- 142
- 0
How would one obtain a Fourier Transform solution of a non homogeneous heat equation? I've arrived at a form that has
[tex]\frac{\partial }{ \partial t }\hat u_c (\omega,t) + (\omega^2 + 1)\hat u_c (\omega,t) = -f(t)[/tex]
My professor gave us the hint to use an integrating factor, but I don't see how this would work. If [tex]p(x) = (\omega^2 + 1)[/tex], and [tex]q(x) = -f(t)[/tex], then the integrating factor would be [tex]e^{\int(\omega^2 +1)dw}[/tex]
Multiplying through by this would not give the usual integrating factor form of (..)' on the left hand side. Can anyone help?
[tex]\frac{\partial }{ \partial t }\hat u_c (\omega,t) + (\omega^2 + 1)\hat u_c (\omega,t) = -f(t)[/tex]
My professor gave us the hint to use an integrating factor, but I don't see how this would work. If [tex]p(x) = (\omega^2 + 1)[/tex], and [tex]q(x) = -f(t)[/tex], then the integrating factor would be [tex]e^{\int(\omega^2 +1)dw}[/tex]
Multiplying through by this would not give the usual integrating factor form of (..)' on the left hand side. Can anyone help?