Could someone explains what's gone wrong here?

  • Thread starter Firepanda
  • Start date
In summary, the conversation discusses the mistake in the argument that the derivative of x^2 with respect to x is actually x. The argument disregards the definition of the derivative and does not consider the "x times" part of the function. Furthermore, it is not valid for all values of x, such as negative or fractional values.
  • #1
Firepanda
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I just read this on another forum

'We know that the derivative of x^2 with respect to x is 2x. However, what if we rewrite x^2 as the sum of x x's, and then take the derivative:

d/dx[ x^2 ] = d/dx[ x + x + x + ... (x times) ]
= d/dx[x] + d/dx[x] + d/dx[x] ... (x times)
= 1 + 1 + 1 + ... (x times)
= x

This argument shows that the derivative of x^2 with respect to x is actually x. So what's going on here?'

Wheres the mistake? :P
 
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  • #2
What happens if x is not a positive integer? What if x is negative or a fraction like 1/2? How would it evaluate?

However, that's not all that's wrong with this argument. Are you familiar with the definition of the derivative? If you are, then take a closer look at the definition to see if this method is still valid under the original fundamental definition.
 
  • #3
The function
[tex]f(x)= 5x= (5+ 5\c+ 5 \cdot\cdot\cdot+ 5)[itex] {x times}
is a function of x: your method would say
[itex]f'(x)= (0+ 0+ 0\cdot\cdot\cdot+ 0)= 0[/itex]
which is, of course, not true.
[itex]f(x)= x^2= (x+ x+ \cdot\cdot\cdot+ x)[/itex] {x times}

is a function of x in two ways. You have not taken into account the "x times" part of the function.
 

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