In a cavity 12.5 cm by 3.9 cm, with Y being 12.5 cm and X/Z being 3.9,

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In summary, the conversation discusses how to calculate the resonance for a cavity with specific dimensions and conditions. The volume is filled with air and the sidewalls are not rigid, with one end assumed to be open. The speaker offers to provide more information if needed and encourages the individual seeking help to share their progress and difficulties to receive assistance.
  • #1
echoaa23
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In a cavity 12.5 cm by 3.9 cm, with Y being 12.5 cm and X/Z being 3.9, how would you calculate the resonance for that internal volume. The volume is filled with air and the sidewalls are not rigid. This is also assuming that one end is open.

I can, of course, give more information if it's needed...
 
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Welcome to PF!

echoaa23 said:
In a cavity 12.5 cm by 3.9 cm, with Y being 12.5 cm and X/Z being 3.9, how would you calculate the resonance for that internal volume. The volume is filled with air and the sidewalls are not rigid. This is also assuming that one end is open.

I can, of course, give more information if it's needed...

Hi echoaa23! Welcome to PF! :smile:

(which end is open? :wink:)

Show us what you've tried, and where you're stuck, and then we'll know how to help you! :smile:
 
  • #3


To calculate the resonance for this internal volume, we can use the formula for the fundamental frequency of a closed-end cylindrical air column, which is f = (n/2L) * (v/λ), where n is the harmonic number, L is the length of the air column, v is the speed of sound in air, and λ is the wavelength.

In this case, n = 1 (fundamental frequency), L = 12.5 cm (length of the cavity), and v = 343 m/s (speed of sound in air at room temperature). To calculate the wavelength, we can use the formula λ = 4L/(n+1), which in this case gives us a wavelength of 50 cm.

Plugging these values into the formula, we get f = (1/2*0.125m) * (343m/s/0.5m) = 1372 Hz.

However, since the sidewalls are not rigid, the resonance frequency may be slightly different due to the flexibility of the walls. In this case, we can use the formula for the fundamental frequency of an open-end cylindrical air column, which is f = (n/2L) * (v/2L), where n is the harmonic number, L is the length of the air column, and v is the speed of sound in air.

Using the same values as before, we get f = (1/2*0.125m) * (343m/s/0.25m) = 2744 Hz.

It's important to note that these calculations are only estimates and the actual resonance frequency may vary depending on the exact dimensions and properties of the cavity. Additionally, other factors such as temperature and humidity can also affect the resonance frequency.
 

1. What does "Y being 12.5 cm" mean in this context?

Y being 12.5 cm refers to the length of one side of the cavity, which is 12.5 cm. This measurement is used to describe the dimensions of the cavity.

2. How are X and Z related in this cavity?

In this context, X and Z represent the width and height of the cavity, respectively. Since they both have the same measurement of 3.9 cm, it can be assumed that the cavity is a square or a cube.

3. What is the volume of this cavity?

To calculate the volume of a cavity, the length, width, and height must be multiplied together. In this case, the volume would be 12.5 cm x 3.9 cm x 3.9 cm, which equals 192.375 cubic centimeters.

4. How would you measure the dimensions of this cavity?

To measure the dimensions of this cavity, a ruler or measuring tape could be used. The length would be measured along the Y side (12.5 cm), and the width and height would be measured along the X and Z sides (both 3.9 cm).

5. Is this cavity considered large or small in comparison to other cavities?

The size of this cavity can be considered relative, as it depends on what other cavities are being compared to. However, in general, a cavity with dimensions of 12.5 cm x 3.9 cm x 3.9 cm is relatively small compared to other cavities that may be larger in all three dimensions.

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