How Long Does It Take for an Object to Fall to the Ground?

  • Thread starter jamesd2008
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In summary, if you don't know the height of an object, you can determine how long it will take it to hit the ground by using the equation: h = \frac{1}{2} g t^2. If you allow the object to fall without pushing it down, the initial velocity is zero.
  • #1
jamesd2008
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Hi,

If you no the height of an object only, assuming no frictional forces, and that it is on earh. Can you determine how long it will take to hit the ground?

Thanks
James
 
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  • #2
Also the final velocity is also unknown and the initial velocity is zero?
 
  • #3
I am assuming that you're talking about the height between the object and the floor. The answer is yes, and that is obvious from the equations that describe free fall, meaning the fall that is induced and preserved only by the force of gravitational attraction that the Earth exerts on the body.

So we have
[itex]h = \frac{1}{2} g t^2 \Leftrightarrow t = \sqrt{\frac{2h}{g}} [/itex]
and since you know h, you can calculate the required time. Using that t you can solve for the final velocity of the body, the one it has right before it reaches ground. And yes, since you let the body go at one point without pushing it downwards, the initial velocity is zero.
 
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  • #4
karkas said:
I am assuming that you're talking about the height between the object and the floor. The answer is yes, and that is obvious from the equations that describe free fall, meaning the fall that is induced and preserved only by the force of gravitational attraction that the Earth exerts on the body.

So we have
[itex]h = \frac{1}{2} g t^2 \Leftrightarrow t = \sqrt{2gh} [/itex]
and since you know h, you can calculate the required time. Using that t you can solve for the final velocity of the body, the one it has right before it reaches ground. And yes, since you let the body go at one point without pushing it downwards, the initial velocity is zero.

No t=square root (2h/g)
velocity = square root (2gh)
 
  • #5
Yes sorry my bad.
 
  • #6
Thanks for the reply's guys, much help :smile:
 

1. How is the time for an object to fall calculated?

The time for an object to fall is calculated using the equation t = √(2h/g), where t is the time in seconds, h is the height in meters, and g is the acceleration due to gravity (9.8 m/s²).

2. Does the mass of the object affect the time it takes to fall?

No, the mass of the object does not affect the time it takes to fall. The time is only dependent on the height and acceleration due to gravity.

3. How does air resistance affect the time for an object to fall?

Air resistance can affect the time for an object to fall by slowing it down. The more surface area an object has, the more air resistance it will experience, causing it to take longer to fall.

4. Does the time for an object to fall change on different planets?

Yes, the time for an object to fall can change on different planets. This is because the acceleration due to gravity varies on different planets. For example, on Mars, the acceleration due to gravity is 3.7 m/s², so an object will take longer to fall compared to on Earth.

5. Can the time for an object to fall be affected by the shape of the object?

Yes, the shape of an object can affect the time it takes to fall. Objects with a larger surface area will experience more air resistance and take longer to fall. Additionally, objects with a streamlined shape will experience less air resistance and fall faster than objects with a bulky shape.

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