Calculate the potential difference induced in the circuit as a function of time

In summary, the problem involves a square circuit in a uniform magnetic field, rotating about the x-axis with a uniform angular speed. The goal is to calculate the potential difference induced in the circuit as a function of time by considering the angle between the surface normal and the field. This is done by expressing the angle theta in terms of time and differentiating the potential difference equation with respect to time to get BA omega sin (omega*t).
  • #1
blueyellow

Homework Statement



A square circuit with side L lies in the x-y plane, is centred on the origin and has sides parallel to the x and y axes. At time t=0 it starts turning about the x axis, in a region characterised by a uniform magnetic field B parallel to z, with uniform angular speed omega. By considering the angle between the surface normal and the field, calculate the potential difference (electromotive force) induced in the circuit as a function of time.

Homework Equations



phi(subscript B)=BA cos theta

potential difference=-d(phi (subscript b))/dt

The Attempt at a Solution



potential difference=-d(BA cos theta)/dt

this isn't leading anywhere. I don't know how to differentiate it with respect to t
 
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  • #2
You need to express the angle theta (angle between surface normal and field lines) in terms of time. (theta starts from 0 degrees)
 
Last edited:
  • #3
thank you, Pi-bond

potential difference=-d(BA cos omega*t)/dt

=BA omega sin (omega*t)

correct?
 
  • #4
Yes, that is correct.
 
  • #5
.

As a scientist, it is important to approach problems with a systematic and logical approach. In this case, we can start by breaking down the problem into smaller parts and identifying any relevant equations or principles that can help us solve it.

Firstly, we can recognize that the potential difference induced in the circuit is a result of Faraday's law of induction, which states that a changing magnetic field can induce an electric field. In this case, the changing magnetic field is due to the rotation of the circuit.

Next, we can use the equation for magnetic flux, phi(subscript B)=BA cos theta, where B is the magnetic field, A is the area of the circuit, and theta is the angle between the surface normal and the magnetic field.

Since the circuit is rotating about the x axis, the angle between the surface normal and the magnetic field will be changing with time. We can express this angle as a function of time, theta(t)=omega*t, where omega is the angular speed.

Substituting this into the equation for magnetic flux, we get phi(subscript B)=BA cos (omega*t).

Finally, we can use the equation for potential difference induced by a changing magnetic flux, potential difference=-d(phi(subscript B))/dt.

Taking the derivative with respect to time, we get potential difference=-BA omega sin (omega*t).

Therefore, the potential difference induced in the circuit as a function of time is given by the equation potential difference=-BA omega sin (omega*t). This shows that the potential difference will vary sinusoidally with time, with a maximum value of BA omega and a minimum value of -BA omega.

In conclusion, by considering the angle between the surface normal and the magnetic field, we were able to calculate the potential difference induced in the circuit as a function of time using principles from electromagnetism. This approach can be applied to other problems in physics, where breaking down the problem and using relevant equations and principles can help us find a solution.
 

1. What is the formula for calculating the potential difference induced in a circuit?

The formula for calculating the potential difference induced in a circuit is V = -N * dφ/dt, where V is the induced potential difference, N is the number of turns in the coil, and dφ/dt is the rate of change of magnetic flux through the coil.

2. How is time related to the potential difference induced in a circuit?

The potential difference induced in a circuit is directly proportional to the rate of change of magnetic flux through the coil, which is also known as the time derivative. This means that as time increases, the potential difference will also increase.

3. What factors can affect the potential difference induced in a circuit?

The potential difference induced in a circuit can be affected by the number of turns in the coil, the strength of the magnetic field, and the speed at which the magnetic field changes.

4. Can the direction of the induced potential difference change?

Yes, the direction of the induced potential difference can change depending on the direction of the changing magnetic field. According to Lenz's law, the induced potential difference will always be in a direction that opposes the change in magnetic flux.

5. How does the potential difference induced in a circuit affect the flow of current?

The potential difference induced in a circuit can cause a flow of current if the circuit is closed and there is a conducting path for the current to follow. The direction of the current will be determined by the direction of the induced potential difference and the resistance of the circuit.

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