Decomposing the direct sum as direct product

In summary, the conversation discusses a basic question in angular momentum in quantum mechanics and the strategy for proving the general statement for spin representations. This topic is covered in many quantum mechanics books, such as Cohen-Tannoudji's text and books on group theory with applications to physics. The decomposition can be obtained by counting the number of states in a system with spin, and grouping these states into sets with definite j values.
  • #1
elduderino
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This is a basic question in angular momentum in quantum mechanics that I am studying.
I know that [tex]\frac{1}{2}\otimes \frac{1}{2} = 1\oplus 0[/tex] What would be a strategy to proving the general statement for spin representations [tex]j\otimes s =\bigoplus_{l=|s-j|}^{|s+j|} l[/tex]
 
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  • #2
This is typically treated in every book of quantum mechanics. Use for example the second volume of Cohen - Tannoudji's text. The famous grid-proof is there. Or any books on group theory with applications to physics (this is typically the Clebsch-Gordan theorem for SU(2)).
 
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  • #3
elduderino, The decomposition can be obtained just by counting the number of states. A system with spin s has 2s + 1 states, one for each value of m running from m = s, s-1,... down to m = -s. Now look at the states in the product ℓ ⊗ s. There will be one state with m = ℓ+s, two states with m = ℓ+s-1, ... down to s states with m = ℓ-s (assuming s <= ℓ). If you try grouping these states into sets with definite j values, you will find it necessary to use j = ℓ+s, ... down to j = ℓ-s, and each of these j values will be needed exactly once.
 

1. What is the concept of decomposing the direct sum as direct product?

Decomposing the direct sum as direct product is a mathematical process of breaking down a direct sum of vector spaces into a direct product of smaller vector spaces. This allows for a better understanding and analysis of the structure of the original direct sum.

2. Why is it important to decompose the direct sum as direct product?

Decomposing the direct sum as direct product is important because it simplifies the understanding and manipulation of vector spaces. It also allows for the identification of independent subspaces within the original direct sum, which can be useful in solving complex problems.

3. What is the difference between direct sum and direct product?

Direct sum and direct product are both mathematical operations involving vector spaces. The main difference is that direct sum combines vector spaces, while direct product multiplies them. Direct sum is used to find the total space of two or more vector spaces, while direct product is used to find all possible combinations of elements from different vector spaces.

4. How can decomposing the direct sum as direct product be applied in real life?

Decomposing the direct sum as direct product has various applications in fields such as physics, engineering, and computer science. It can be used to analyze and model complex systems, such as circuits or chemical reactions. It also has applications in data compression and error correction algorithms.

5. Are there any limitations to decomposing the direct sum as direct product?

Yes, there are limitations to decomposing the direct sum as direct product. It can only be applied to vector spaces that are finite-dimensional and have a finite number of subspaces. In addition, the direct sum must have a finite number of terms. If these conditions are not met, the direct sum cannot be decomposed as a direct product.

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