Mass-spring-mass system rotating about its centre of mass relativistically

In summary, we can use the equations for total energy and angular momentum to find a relation between J and E for a rotating system with two equal masses attached to a spring. This relation involves the relativistic mass equation, Hooke's law, and the centripetal force.
  • #1
aayush.saxena
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Homework Statement



2 equal masses 'm' are attached to a spring of spring constant 'K' and unstretched length 'L'. The system is rotating about its centre of with an angular velocity 'w'. The linear velocity 'v' of m is comparable to that of speed of light 'c'. Find a relation between the Angular Momentum 'J' and the total energy 'E'.

Homework Equations



Hooke's law.
Centripetal force.
relativistic mass equation.

The Attempt at a Solution



I started off by equating the Force in the spring K (2r - L), where 2r is the compressed length of the spring; with the Centripetal force γm.w^2.r

I obtained the expression for r using this. Using r, i obtained the Angular momentum using J = (2γm).w.r^2

Now I cannot figure out how to obtain a relation between J and the total energy E.

Help? Thanks in advance.
 
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  • #2


To find a relation between the Angular Momentum J and the total energy E, we can use the following steps:

1. Start by writing the equation for the total energy of the system, which includes both the kinetic energy and potential energy. For a rotating system, the total energy can be expressed as:

E = KE + PE = 1/2mv^2 + 1/2K(2r-L)^2

2. Next, we can use the relativistic mass equation to express the mass m in terms of its rest mass mo and the velocity v. This gives us:

m = mo/√(1-(v/c)^2)

3. Now, we can substitute this expression for m into the equation for total energy, and also use the expression for r that you obtained earlier. This gives us:

E = 1/2(mo/√(1-(v/c)^2))v^2 + 1/2K(2(γm)w^2r^2-L)^2

4. Simplifying and rearranging, we get:

E = (mo/2)(v^2/√(1-(v/c)^2)) + K(γm)^2w^2(r^2-L)^2

5. Finally, we can use the expression for Angular Momentum that you obtained earlier, J = (2γm)w(r^2), and substitute it into the equation for total energy. This gives us the desired relation between J and E:

E = (mo/2)(v^2/√(1-(v/c)^2)) + KJ^2/(4γ^2m^2(r^2-L)^2)

This is the final relation between Angular Momentum J and total energy E for the given system.
 

1. What is a mass-spring-mass system rotating about its centre of mass relativistically?

A mass-spring-mass system rotating about its centre of mass relativistically is a physical system that consists of two masses connected by a spring, rotating around a fixed point that is located at the centre of mass of the system. Relativistic effects come into play when the rotational speed of the system approaches the speed of light.

2. How does the relativistic rotation of the mass-spring-mass system affect its behavior?

The relativistic rotation of the mass-spring-mass system causes changes in its behavior, such as an increase in its mass due to relativistic mass increase, a decrease in the length of the spring due to length contraction, and changes in the system's energy due to time dilation.

3. What is the equation for the relativistic rotational energy of a mass-spring-mass system?

The equation for the relativistic rotational energy of a mass-spring-mass system is E = mc2 / √(1 - v2/c2) - mc2, where m is the mass of the system, c is the speed of light, and v is the rotational speed of the system.

4. How does the relativistic mass increase affect the frequency of the mass-spring-mass system's oscillations?

The relativistic mass increase causes the frequency of the mass-spring-mass system's oscillations to decrease as the rotational speed approaches the speed of light. This is due to the increase in the system's mass, which makes it harder for the spring to oscillate at a faster rate.

5. What are some real-world applications of the mass-spring-mass system rotating about its centre of mass relativistically?

One potential application of this system is in the design of gyroscopes, which are used in navigation systems and other devices that require precise rotational motion. Understanding the relativistic effects on the behavior of this system can help in the development of more accurate and efficient gyroscopes. Additionally, studying this system can further our understanding of relativistic mechanics and its applications in various fields of science and engineering.

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