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Coulomb interaction not affected by presence of other charges 
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#1
Jul2414, 02:38 AM

P: 176

One of the observation noted in connection with coulomb interaction is that, it is not affected by the presence of other charges. Why?
Thanks. 


#2
Jul2414, 03:01 AM

P: 234

Could you possibly tell us where you read that? It doesn't sound quite right, but perhaps I misunderstand you.
From the law of superposition, we can write the effect of a set of N point charges q on a charge as [itex] F(r) = \frac{q}{4 \pi \epsilon_0}\sum_{i=1}^N \widehat{R}_i /R_i^2[/itex] Where [itex]\widehat{R}_i [/itex] is a unit vector in the direction of [itex] R_{i} = r  r_{i}[/itex]. Is this perhaps what you meant? This is just due to the linearity of the electrostatic interaction  any linear system may be decomposed into a linear superposition, wikipedia has an ok writeup. 


#3
Jul2414, 04:41 AM

P: 176

I read it on the twelve standard book of my state board.
Also I found the same on this site. http://www.askiitians.com/iitjeeel.../coulombslaw/ Following observations can be noted in connection with Coulomb’s interaction: (a)... (b).. (c)Coulombs interaction is not affected by the presence of other charges in the neighborhood. What exactly does it say? 


#4
Jul2414, 05:04 AM

P: 234

Coulomb interaction not affected by presence of other charges
I find that statement vauge too, but I would interpret it as I stated above  that the law of superposition holds.



#6
Jul2414, 08:32 AM

P: 176

What I understand from superposition principle, is that all the charges when placed near each other behave independently of each other and just only their vector sum add up. May be this is what the statement mean. And thanks for the reply. 


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